A bucket holds c liters of water, but a jar holds 8 liters less. How many times as much water can the bucket hold as the jar?

You deposit $400 in an account that pays 2.4% annual interest compounded monthly a. When does your balance first exceed $500? af

Zina [12379]

Answer:

The final result is $88

Step-by-step explanation:

The Math.random () method produces a floating-point, pseudo-random number ranging from 0 to 1 (including 0 but excluding 1), which is distributed fairly evenly within that interval — allowing you to scale it to fit your preferred range.

3 0

2 months ago

An electronic product contains 40 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the

Zina [12379]

Answer:

The chance that there is one or more defective integrated circuits is 33.10%.

Detailed solution:

Each integrated circuit can be either defective or not, which provides only two possible outcomes. As a result, this scenario is well-suited to be analyzed using the binomial probability distribution.

About the binomial distribution

This distribution calculates the likelihood of exactly x successes in n repeated trials where each trial has two possible results.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

Here, $C_{n,x}$ represents the count of combinations of x items selected from n elements, described by the formula:

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of the event X occurring.

Applying it to the problem

The product contains 40 integrated circuits, so $n = 40$ .

The probability that an individual integrated circuit is defective is 0.01, so $\pi = 0.01$ .

Finding the probability of at least one defective circuit

There are two cases: either at least one integrated circuit is defective (probability $P(X > 0)$ ) or none are defective (probability $P(X = 0)$ ). Since probabilities sum to 1, we want to determine $P(X>0)$ .

$P(X > 0) + P(X = 0) = 1$

$P(X > 0) = 1 - P(X = 0)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{40,0}.(0.01)^{0}.(0.99)^{40} = 0.6690$

$P(X > 0) = 1 - P(X = 0) = 1 - 0.6690 = 0.3310$

Hence, the probability of having one or more defective integrated circuits is 33.10%.

3 0

3 months ago

Read 2 more answers

There was 5/8 of a pie left in the fridge. Daniel are 1/4 of the left over pie. How much of a pie did he eat

AnnZ [12381]

Answer:

vvvv

Step-by-step explanation:

1. Convert 1/4 into eighths to be able to subtract it from 5/8.

1/4 x 2 = 2/8

2. Deduct 2/8 from 5/8.

5/8 - 2/8 = 3/8

Daniel consumed 2/8 of the remaining pie, and now there are 3/8 left.

7 0

2 months ago

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If 65% of a number is 1,105, what is 82% of the number?

Inessa [12570]

To find the original number where 65% equals 1105:
0.65x = 1105
x = 1105 ÷ 0.65
x = 1700... hence, the original number is 1700.

Calculating 82% of 1700:
0.82 * 1700 = 1394 <== this is your answer.

6 0

2 months ago

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Part of a book fell out. The first page of this part has number 143. The last page has a number written with the same digits. Ho

AnnZ [12381]

142 pages. Step-by-step explanation: The provided parameters state that the first page of the lost portion of the book is numbered 143. The last page has the same digits as 143. As the book is divided into two segments, one segment begins at page one, while the other follows after the first segment ends. Therefore, the pages in the first section are numbered from 1 up to the first page of the second part minus one, which means the missing part of the book contains pages from 1 to 142, resulting in 142 pages.

3 0

1 month ago