The result is 3.6y. By multiplying 0.3 by 12, we arrive at 3.6, and we include the variable y.
Answer:
The chance of completing the entire package installation in under 12 minutes is 0.1271.
Step-by-step explanation:
We define X as a normal distribution representing the time taken in seconds to install the software. According to the Central Limit Theorem, X is approximately normal, where the mean is 15 and variance is 15, giving a standard deviation of √15 = 3.873.
To find the probability of the total installation lasting less than 12 minutes, which equals 720 seconds, each installation should average under 720/68 = 10.5882 seconds. Thus, we seek the probability that X is less than 10.5882. To do this, we will apply W, the standard deviation value of X, calculated via the formula provided.
Utilizing
, we reference the cumulative distribution function of the standard normal variable W, with values found in the attached file.

Given the symmetry of the standard normal distribution density function, we ascertain
.
Consequently, the probability that the installation process for the entire package is completed within 12 minutes is 0.1271.
Response:
6 servings.
Detailed explanation:
To determine this, divide 3/4 by 1/8, here are the steps:
3/4 divided by 1/8
3/4 times 8/1
(3 × 8 = 24); (4 × 1 = 4)
24 divided by 4 results in 6.
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Answer:
Option C is the right choice.
Step-by-step explanation:
The given coordinates define a rectangle, and our objective is to show that the diagonals JL and KM are congruent.
We know that rectangles possess four right angles.
To prove the congruence of the diagonals JL and KM, we will utilize the Pythagorean theorem.
In triangle KLM, KL has a length of b units while LM has a length of a units. By applying the Pythagorean theorem 
In triangle JML, JM is b units long, and LM remains a units long. We again can apply the Pythagorean theorem
Thus, we find that
and option C is the correct choice.
Answer:
Step-by-step explanation:
Player A has a red marble and a blue marble, while Player B also has a red marble and a blue marble.
Therefore, the probability of selecting one marble is equal, at 0.5.
Due to the independence of A and B's choices, the joint event is calculated by multiplying the probabilities.
Let A represent the amount that player A wins.
If both players select one marble, the sample space can be considered as
(R,R) (R,B) (B,R) (B,B)
Probability 0.25 0.25 0.25 0.25
A's winnings 3 -2 -2 1
E(A) 0.75 -0.5 -0.5 0.25 = 0
Thus, the game is even, offering equal expected values for both A and B.
It does not influence the outcome whether you are A or B.