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slava
12 days ago
13

Two players A and B play a marble game. Each player has both a red and blue marble. They present one marble to each other. If bo

th present red, A wins $3. If both present blue, A wins $1. If the colors of the two marbles do not match, B wins $2. Is it better to be A, or B, or does it matter?
Mathematics
1 answer:
Zina [3.9K]12 days ago
5 0

Answer:

Step-by-step explanation:

Player A has a red marble and a blue marble, while Player B also has a red marble and a blue marble.

Therefore, the probability of selecting one marble is equal, at 0.5.

Due to the independence of A and B's choices, the joint event is calculated by multiplying the probabilities.

Let A represent the amount that player A wins.

If both players select one marble, the sample space can be considered as

             (R,R)  (R,B)  (B,R) (B,B)

Probability     0.25  0.25  0.25  0.25

A's winnings          3       -2     -2       1

E(A)      0.75   -0.5    -0.5   0.25   =    0

Thus, the game is even, offering equal expected values for both A and B.

It does not influence the outcome whether you are A or B.

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Two planes A and B can each fly through still air at 550 mph. The distance from Paris to Los Angeles is 5000 miles. Wind blows f
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Answer:2688.63 miles

Step-by-step explanation:

Given

The distance from Paris to Los Angeles d=5000 miles

Wind traveling at 100 mph from Los Angeles to Paris

The velocity of the plane through still air is v=550 mph

Relative velocity of Plane A is v_a=550-100 =450 mph since Plane A is heading against the wind

Relative velocity of Plane B is v_b=550+100=650 mph

Plane A departs at noon

Distance covered by Plane A in 1 hour =450\times 1=450 miles

The total separation distance between the planes is 5000-450=4550 miles

Assuming they meet after t hours

Distance covered by Plane B in that time frame =v_b\times t=650\times t

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The total distance equals 4550 miles

4550=650t+450t

t=\frac{4550}{1100}

t=4.13 hr

Distance traveled by B is =650\times 4.136=2688.63 miles

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Step-by-step explanation:

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