One hundred teachers attended a seminar on mathematical problem solving. The attitudes of representative sample of 12 of the tea

Detailed derivation:

dA/dt = 6 - 0.02A

dA/dt = -0.02 (A - 300)

Rearranging terms.

dA / (A - 300) = -0.02 dt

Integrate both sides.

ln(A - 300) = -0.02t + C

Isolate A.

A - 300 = Ce^(-0.02t)

A = 300 + Ce^(-0.02t)

Apply initial condition to determine C.

50 = 300 + Ce^(-0.02 × 10)

50 = 300 + Ce^(-0.2)

-250 = Ce^(-0.2)

C = -250e^(0.2)

A = 300 - 250e^(0.2)e^(-0.02t)

A = 300 - 250e^(0.2 - 0.02t)

Answer:

zero slope

Step-by-step explanation:

Hope this information is helpful:)

Answer:

F(n)= 0.50+0.15

Step-by-step explanation:

The starting point is 0.50. Additionally, when adding a fine of 0.15, you would consider 0.15 as well.

The question appears to be incomplete. Here’s the complete inquiry:

Samir is quite skilled with the gun. When he targets a specific aim at the shooting range, he has a 0.95 probability of striking it. On one occasion, Samir sets out to shoot 10 targets consecutively.

If he has the same chance of hitting each of the 10 targets, what is the likelihood that he will miss at least one?

Response:

40.13%

Step-by-step breakdown:

Let 'A' represent the event of successfully hitting all targets in 10 trials.

The complement of 'A' is

Now, since Samir has a consistent probability of hitting each target at 0.95.

Now,

We know that the combined probability of an event and its complement equals 1.

Consequently, the probability that he misses at least one target among 10 attempts is 40.13%.