Answer:
The resulting value is 2.381
Step-by-step explanation:
Using the information presented in the question, we will calculate the evidence supporting the professor's hypothesis
Given that:
x₁ = 74,
n₁ = 36
s₁ = 8
x₂ = 68
n₂ = 36
s₂ = 10
The hypotheses can be outlined as:
The critical value is t₃₆+₃₆-₂,₀.₀₁ = t₇₀,₀.₀₁
thus,
t₃₆+₃₆-₂,₀.₀₁ = t₇₀,₀.₀ = 2.381
This implies a range of -2.381 to 2.381
Thus, we can support the professor's assertion.
Part 1) side 1=15'-7" side 2=20'-4" side 3=26'-2" To determine the total length of all three sides, add them together: total length=side 1+side 2 +side 3. By substituting, total length=15'-7"+20'-4"+26'-2" can be expressed as total length=(15'+20'+26')+(7"+4"+2"). This simplifies to total length=(61')+(13"). Keep in mind that 12"=1', so 13" can be expressed as 12"+1"=1'+1". By substituting again: total length=(61')+(1'+1") simplifies to total length=(62')+(1") which leads to 62'-1". Therefore, the total length of the three sides is 62'-1".
Answer:
Step-by-step explanation:
a) According to the included image, the smaller section measures 16ft², and the larger section is 50 ft². The formula for the area of a square is side × side = side².
For the smaller section: Area = side²
16 = side²
side = √16 = 4 ft
For the larger section: Area = side²
50 = side²
side = √50
The overall length of the shed is the small area plus the large area = 4 + √50
The total length of the shed equates to 4 + √50
b) All square roots of integers unless they are perfect squares are irrational numbers, thus 4 + √50 is irrational. All such values fall within the set of real numbers, categorizing 4 + √50 as an irrational and real number.
Approximate length of wire ≈ 193 ft (to the nearest foot).
