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8 days ago

10

A long wire is attached to the top of a 175 foot tall electrical transmission tower. If the wire needs to an angle of 65 degrees

with the ground, then how long must it be? Round your answer to the nearest foot.

1 answer:

tester [8.8K]8 days ago

5 0

Approximate length of wire ≈ 193 ft (to the nearest foot).

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Four hot air balloons each descend 295 feet per minute for 7 minutes. Find the total change in altitude for all 4 balloon

Svet_ta [9518]

Answer: A total descent of 8260 feet occurred for all four balloons.

Step-by-step explanation:

Based on the information provided:

Number of hot air balloons = 4

Minutes of descent = 7

Descent rate per minute = 295 feet

Thus, the overall change in altitude for all four balloons can be calculated as:

$295\times 7\times 4\\\\=8260\ feet$

Thus, a total descent of 8260 feet was experienced by the four balloons.

7 0

17 days ago

Read 2 more answers

An experiment was conducted to record the jumping distances of paper frogs made from construction paper. Based on the sample, th

tester [8842]

Answer:

$9.9676 - 2.326*0.5904 =8.594$

$9.9676 + 2.326*0.5904 =11.341$

Step-by-step explanation:

Notation

$\bar X$ is the sample mean

$\mu$ indicates the population mean (the variable of interest)

s signifies the sample standard deviation

n denotes the sample size

Solution to the problem

The mean's confidence interval is derived from the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In this instance, the 9% confidence interval corresponds to:

$8.8104 \leq \mu \leq 11.1248$

We can determine the mean using the following:

$\bar X = \frac{8.8104 +11.1248}{2}= 9.9676$

Additionally, the margin of error can be calculated as:

$ME= \frac{11.1248- 8.8104}{2}= 1.1572$

The margin of error for this situation is expressed as:

$ME = t_{\alpha/2}\frac{s}{\sqrt{n}} = t_{\alpha/2} SE$

Next, we find the standard error:

$SE = \frac{ME}{t_{\alpha/2}}$

The critical value for a 95% confidence interval using a normal standard distribution is roughly 1.96, and substituting gives us:

$SE = \frac{1.1572}{1.96}= 0.5904$

For the 98% confidence interval, the significance corresponds to $\alpha=1-0.98= 0.02$ and $\alpha/2 = 0.01$ with a critical value of 2.326, yielding a confidence interval of:

$9.9676 - 2.326*0.5904 =8.594$

$9.9676 + 2.326*0.5904 =11.341$

8 0

16 days ago

If m<9=97° and m<12=114°, find each measure. I have to show my work.

Leona [9271]

Solution/Step-by-step breakdown:

Information provided:

m<9 = 97°

m<12 = 114°

a. m<1 = m<9 because they are corresponding angles, which are equal.

m<1 = 97° (using substitution)

b. m<2 + m<1 = 180° (since they form a linear pair)

m<2 + 97° = 180° (substitute the value)

m<2 = 180 - 97 (subtracting 97 from both sides)

m<2 = 83°

c. m<3 = m<11 (as they are corresponding angles)

m<11 + m<12 = 180° (linear pair)

m<11 + 114° = 180° (substituting the known angle)

m<11 = 180 - 114

m<11 = 66°

m<3 = m<11 = 66°

d. m<4 + m<3 = 180° (linear pair)

m<4 + 66° = 180° (substituting the known angle)

m<4 = 180 - 66

m<4 = 114°

e. m<5 = m<2 as vertical angles are equal.

m<5 = 83° (using substitution)

f. m<6 = m<1 (vertical angles are equal)

m<6 = 97° (using substitution)

g. m<7 = m<4 (as vertical angles are equal)

m<7 = 114° (using substitution)

h. m<8 = m<3 (due to vertical angles being equal)

m<8 = 66° (using substitution)

i. m<10 = m<2 (corresponding angles are equal)

m<10 = 83° (using substitution)

j. m<11 = m<3 (because they are vertical angles)

m<11 = 66° (using substitution)

k. m<13 = m<5 (corresponding angles)

m<13 = 83° (applying substitution)

l. m<14 = m<9 (as vertical angles)

m<14 = 97° (applying substitution)

m. m<15 = m<12 (as vertical angles)

m<15 = 114° (applying substitution)

n. m<16 = m<11 (because they are vertical angles)

m<16 = 66° (applying substitution)

3 0

23 days ago

Earyn owns French Twist Hair Salon. She charges $35 for a cut an $120 for a cut and color combo. Yesterday she had seven clients

Leona [9271]

35x + 120y = 500
I hope this makes sense

6 0

11 days ago

A stadium asked for $760,000 for naming rights. During a bidding war for the stadium naming rights, one company bid 7% more than

AnnZ [9104]

Response:

$\$\ 829464$

Detailed explanation:

First company bid:

The bid is $7\%$ more

$7\%$ of $760000=\frac{7}{100}\times760000=53200$

Bid of first $=760000+53200=813200$

Second company bid:

The second company’s bid is $2\%$ higher than the first

$2\%$ of the first bid $=\frac{2}{100}\times 813200=16264$

As a result, the second company's bid is $=813200+16264=829464$

8 0

16 days ago