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levacccp
7 days ago
12

Triangles E F G and E prime F prime G prime are shown. Angles F E G and F prime E prime G prime are 72 degrees. Angles E F G and

E prime F prime G prime are 66 degrees. What additional information could be used to prove ΔEFG ΔE'F'G' using AAS? Check all that apply.
Mathematics
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The total cost of 5 doughnuts and 6 cookies at a bakery is $11.95.The cost of each cookie is $0.95.Select the equation and its s
Zina [12379]

The formula representing this scenario is 5x+6(0.95)=11.95

The answer to this formula is x=1.25

Initially, you need to formulate the equation.

5x+6(0.95)=11.95

Next, simplify the expressions.

5x+5.7=11.95

Afterwards, subtract 5.7 from both sides.

5x=6.25

Lastly, divide both sides by 5

x=1.25

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To find the number in a square multiply the numbers in the two circles connected to it brainly
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Response:

the solution can be found in the image

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1 month ago
Suppose your statistics professor reports test grades as​ z-scores, and you got a score of 1.57 on an exam. ​a) Write a sentence
tester [12383]

Answer:

a) In this case, we have a z-score of 1.57, characterized as:

z =\frac{x -\mu}{\sigma}

This signifies that our score is 1.57 standard deviations above the average of all test scores.

b) P(Z

Using the normal standard distribution or Excel, we computed:

P(Z

This represents 2.275% of the dataset.

Step-by-step explanation:

Previous concepts

Normal distribution denotes a "probability distribution that is symmetric around the mean, indicating that data close to the mean occurs more frequently than data further from it".

The Z-score serves as "a statistical measurement representing a value's relation to the average (mean) of a set, calculated in terms of standard deviations away from the mean".

Solution to the problem

Part a

For this instance, we hold a z-score of 1.57, which is defined as:

z =\frac{x -\mu}{\sigma}

This shows that our score is 1.57 deviations above the overall test score average.

Part b

A z-score of z=-2 indicates that your friend's score is 2 deviations below the other test scores.

Assuming a normal distribution, we can derive the percentage:

P(Z

Using the normal standard distribution or Excel, we discovered:

P(Z

This represents 2.275% of the data.

6 0
3 months ago
What is 65, 124 rounded to the nearest thousand
AnnZ [12381]
65,000. I'm quite certain because a 1 wouldn't be sufficient to shift the 5 higher.
7 0
1 month ago
Read 2 more answers
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