Write a method named removeDuplicates that accepts a string parameter and returns a new string with all consecutive occurrences

Answer:

Here is the C++ code:

#include <iostream> //for utilizing input and output functions

using namespace std; //for defining objects cin cout

int main(){ //beginning of the main function

   double risingLevel; //declares a variable of type double to store the rising level

   cin>>risingLevel; //captures the risingLevel input from the user

   cout<<"Level: "<<risingLevel<<endl; //outputs the rising level

   cout << "Years: 5, Rise: " << risingLevel * 5<<endl; //outputs the increase in ocean level over 5 years

   cout << "Years: 10, Rise: " << risingLevel * 10<<endl; //outputs the increase in ocean level over 10 years

   cout << "Years: 50, Rise: " << risingLevel * 50<<endl; //outputs the increase in ocean level over 50 years

}

Explanation:

The functioning of the program is as follows:

Supposing the user inputs a rising level of 2.1, then,

risingLevel = 2.1

At that point, the first print statement (cout):

cout<<"Level: "<<risingLevel<<endl; outputs the value of risingLevel to the display. Therefore, this line shows:

Level: 2.1

Next, the program proceeds to the following statement:

   cout << "Years: 5, Rise: " << risingLevel * 5<<endl;

which calculates the increase in ocean levels for a duration of 5 years using the equation:

risingLevel * 5 = 2.1 * 5 = 10.5

It subsequently shows the calculated result on the display. So, this line shows:

Years: 5, Rise: 10.5 Then, the control shifts to the next statement:

   cout << "Years: 10, Rise: " << risingLevel * 10<<endl;

that computes the rise in ocean levels over a span of 10 years using the equation:

risingLevel * 10 = 2.1 * 10 = 21

It then showcases the calculated figure on the output screen. Thus, the output is:

Years: 10, Rise: 21

Next, the program control progresses to this statement:

   cout << "Years: 50, Rise: " << risingLevel * 50<<endl;

which determines the rise in ocean levels for a duration of 50 years using the equation:

risingLevel * 50 = 2.1 * 50 = 105

This then displays the computed result on the output screen, leading to the output:

Years: 50, Rise: 105 Consequently, the complete output from the program will be:

Level: 2.1 Years: 5, Rise: 10.5

Years: 50, Rise: 105

Affirmative.

Data processing entails transforming raw data and managing its flow through the Central Processing Unit and Memory to output devices. A computer's CPU contains two main parts: the Arithmetic Logic Unit (ALU) and the control unit. The ALU handles complex calculations and logical operations, while the control unit retrieves, decodes instructions, and regulates the data exchange between Memory, ALU, primary and secondary storage, along with various output devices.

Response: C

Clarification:

The reason is that four binary bits are insufficient to represent the number sixteen. The maximum is 15.

Respuesta: Te proporcioné 6 opciones de las cuales puedes elegir.

Integridad

Escalabilidad

Calidad de Servicio

Tolerancia a Fallos

Redes de Línea Eléctrica

Seguridad

The code relevant to the problem in question:

import java.util.Scanner;

public class Test {

   public static void main(String[] args) {

       double number;

       double squareRootOfNumber;

       String userInput = null;

       Scanner scanner = new Scanner(System.in);

       System.out.println("Please enter a number: ");

       userInput = scanner.next();

       number = Double.parseDouble(userInput);

       squareRootOfNumber = Math.sqrt(number);

       if (number < 0) {

           throw new ArithmeticException("Cannot compute the square root of a negative number");

       }

       System.out.format("The square root of the entered number is %.2f %n", squareRootOfNumber);

   }

}

The program will output:

Please enter a number:

-90

Exception in thread "main" java.lang.ArithmeticException: Cannot compute the square root of a negative number at com..ans.Test.main(Test.java:18)

Explanation:

The standard Java library function java.lang.Math.sqrt does not throw an ArithmeticException for negative arguments, hence there’s no need to enclose your code in a try/catch block.

Instead, we manually trigger ArithmeticException using the throw keyword:

throw new ArithmeticException("Cannot compute the square root of a negative number");