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Assoli18
1 month ago
7

The ratios in an equivalent ratio table are 3:12, 4:16, and 5:20. If the first number in theratio is 10, what is the Second numb

er? Justify your reasoning​
Mathematics
2 answers:
Zina [12.3K]1 month ago
7 0

Answer:

The second number is 40, since the initial number is 5 multiplied by 2, making the second number 20 multiplied by 2. Each of these ratios can be simplified to 1:4.

Step-by-step explanation:

I completed the assignment.:))

AnnZ [12.3K]1 month ago
6 0

Answer:

10:40

Step-by-step explanation:

As the left value increments by 1, the right value increases by 4. Notice how the left sequence proceeds as 3-4-5 correlating with the right sequence as 12-16-20. Consequently, the answer is 10:40 since 10 multiplied by 4 equals 40.

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A rectangle has area 64 m2. Express the perimeter of the rectangle as a function of the length L of one of its sides. State the
Leona [12618]
A rectangle is defined as a two-dimensional figure that features two pairs of equal, parallel sides. Its dimensions consist of length (L) and width (W). The area of a rectangle can be calculated using the formula that multiplies these two dimensions together. The perimeter can be expressed as

P = 2L + 2W.

Given that
A = LW = 64
therefore, W = 64/L.
Substituting this value into the perimeter formula yields

P = 2L + 2(64/L)
P = 2L + 128/L.
3 0
1 month ago
Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and the e
babunello [11817]

Answer:

0.75 = 75% chance that only one tag is lost, provided at least one tag is lost

Step-by-step explanation:

Independent events:

If A and B are independent events, then:

P(A \cap B) = P(A)*P(B)

Conditional probability:

P(B|A) = \frac{P(A \cap B)}{P(A)}

Here

P(B|A) refers to the probability of event B occurring, given that event A has occurred.

P(A \cap B) is the probability of both A and B occurring together.

P(A) is the probability of event A occurring.

In this scenario:

Event A: At least one tag is missing

Event B: Only one tag is missing.

Each tag has a 40% likelihood of being lost, which is equal to 0.4.

Probability of at least one tag missing:

The events can be considered as either no tags are missing or at least one is. Their probabilities sum to 1. Thus

p + P(A) = 1

p is the probability that none are lost. Each tag has a 60% = 0.6 chance of not being lost, and since they are independent,

p = 0.6*0.6 = 0.36

Then

P(A) = 1 - p = 1 - 0.36 = 0.64

Intersection:

The intersection of at least one lost (A) and exactly one lost (B) is precisely one lost.

Then

Probability of at least one lost:

The first being lost (0.4 chance) and the second not lost (0.6 chance)

Or

The first not being lost (0.6 chance) and the second lost (0.4 chance)

So

P(A \cap B) = 0.4*0.6 + 0.6*0.4 = 0.48

Calculate the probability that exactly one tag is lost, given that at least one tag is lost (round to two decimal places).

P(B|A) = \frac{0.48}{0.64} = 0.75

0.75 = 75% likelihood that precisely one tag is lost, assuming at least one tag is lost

8 0
28 days ago
Let an integer be chosen at random from the integers 1 to 30 inclusive. Find the probability that the integer chosen is not even
babunello [11817]
Given that the sequence goes odd, even, odd, and even , there is an equal chance of drawing an odd (<span>not divisible by 2) number as there is for drawing an even number, so the correct option is C.

I appreciate you giving me the opportunity to answer your question. I enjoy assisting others as much as I can, so feel free to reach out if my responses are helpful to you. It really matters to me to know that my contributions support someone in the community who is seeking help. If you require additional assistance, you can send me a PM! I do receive many PMs, so it might take some time for me to reply; I apologize for any delays. Thank you for taking the time to read this, and I wish you a wonderful day! ~ brainily user, Lillyxrose
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5 0
14 days ago
Read 2 more answers
a golfer needs to hit a ball a distance of 500 feet, but there is a 60-foot tall tree that is 100 feet in front of the point whe
Svet_ta [12734]
We can formulate the trajectory of the parabola using the vertex form equation: y = a (x – h)^2 + k. The coordinates for the vertex are at h and k, representing the peak height, thus h = 250 and k = 120. Consequently, the equation becomes y = a (x – 250)^2 + 120. At the starting point where x = 0 and y = 0, we find a: 0 = a (0 – 250)^2 + 120, which simplifies to 0 = a (62,500) + 120, leading to a = -0.00192. The complete equation is y = -0.00192 (x – 250)^2 + 120. To determine y when x = 400, we substitute: y = -0.00192 (400 - 250)^2 + 120, yielding y = 76.8 ft. Hence, the ball clears the tree by 76.8 ft – 60 ft = 16.8 ft.
8 0
1 month ago
Solve the following quadratic equations by extracting square roots.Answer the questions that follow.
babunello [11817]

Answer:

1. x=±4

2. t=±9

3. r=±10

4. x=±12

5. s=±5

Step-by-step explanation:

1. x^2 = 16

By extracting the square root on both sides

\sqrt{x^2}=\sqrt{16}\\\sqrt{x^2}=\sqrt{(4)^2}\\

x=±4

2. t^2=81

Again, take the square root of each side

\sqrt{t^2}=\sqrt{81}\\\sqrt{t^2}=\sqrt{(9)^2}

t=±9

3. r^2-100=0

r^{2}-100=0\\r^2 =100\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{r^2}=\sqrt{100}\\\sqrt{r^2}=\sqrt{(10)^2}

r=±10

4. x²-144=0

We rewrite as x²=144

Applying square roots

\sqrt{x^2}=\sqrt{144}\\\sqrt{x^2}=\sqrt{(12)^2}

x=±12

5. 2s²=50

\frac{2s^2}{2} =\frac{50}{2}\\s^2=25\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{s^2}=\sqrt{25}\\\sqrt{s^2}=\sqrt{(5)^2}

s=±5 ..

4 0
1 month ago
Read 2 more answers
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