Which equation is equivalent to (one-third) Superscript x Baseline = 27 Superscript x + 2? 3 Superscript x Baseline = 3 Superscr

ipt negative 3 x + 2 3 Superscript x Baseline = 3 Superscript 3 x + 6 3 Superscript negative x Baseline = 3 Superscript 3 x + 2 3 Superscript negative x Baseline = 3 Superscript 3 x + 6

Mathematics

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Which fraction is equivalent to StartFraction 2 Over 6 EndFraction? StartFraction 3 Over 7 EndFraction, because StartFraction 2

babunello [11817]

Which equivalent fraction corresponds to $\frac{2}{6}$ ? - $\frac{3}{7}$ since $\frac{2}{6}= \frac{2 + 1}{6 + 1}$ - $\frac{3}{9}$ as $\frac{2}{6}= \frac{1}{3}$ and $\frac{1}{3} = \frac{3}{9}$

- $\frac{3}{12}$ because $\frac{2}{6}= \frac{1}{3}$ and $\frac{1}{3} = \frac{3}{9}$

- $\frac{3}{8}$ since $\frac{2}{6}= \frac{1}{2} = \frac{2+1}{6+2} = \frac{3}{8}$

The answer is

- $\frac{3}{9}$ because $\frac{2}{6}= \frac{1}{3}$ and $\frac{1}{3} = \frac{3}{9}$

A fraction is deemed equivalent if it maintains the same value when expressed in simplest terms. The equivalent to $\frac{2}{6}$ is found in the chosen option;

First, halve both the numerator and denominator by 2

$\frac{2/2}{6/2}$

Then reduce further

2/2 = 1 and 6/2 = 3; Thus;

$\frac{2/2}{6/2} = \frac{1}{3}$

Next, multiply both the numerator and denominator by 3

$\frac{1*3}{3*3} = \frac{3}{9}$

Therefore, $\frac{2}{6}$ equals $\frac{3}{9}$ .

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1 month ago

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The perimeter of the school crossing sign is 102 inches what is the length of each side

Leona [12618]

The total perimeter of the school crossing sign measures 102 inches.
To find the length of each side, knowing the number of sides is necessary.
If it has 5 sides, dividing 102 by 5 results in 20.4 inches per side.
If it has 4 sides, dividing 102 by 4 gives a side length of 25.5 inches.
So, the side length depends on how many sides the sign has.

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3 months ago

Which function has a simplified base of 4RootIndex 3 StartRoot 4 EndRoot? f(x) = 2(RootIndex 3 StartRoot 16 EndRoot) Superscript

tester [12383]

Response:

$f(x)=4\sqrt[3]{16}^{2x}$

Detailed explanation:

You're likely in search of a function with a base that can be simplified to...

$4\sqrt[3]{4}\approx 6.3496$

The functions you seem to be considering appear to be...

$f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x$