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natta225
12 days ago
14

Mary and Julie both have a goal of raising $1000 for charity. Mary raises $12 every 4 days. Julie raises $19 every 6 days. Will

Mary or Julie reach her goal first? Explain.
Mathematics
2 answers:
babunello [3.6K]12 days ago
7 0

Answer:

Julie will reach her goal 21 days ahead of Mary.

Step-by-step explanation:

Both Mary and Julie aim to raise $1000 for charity.

Mary collects $12 every 4 days.

In one day, Mary raises = \frac{12}{4}

= $3

Time required for Mary to accomplish her goal = \frac{1000}{3}

= 333.33  ≈ 334 days

Julie accumulates $19 every 6 days.

In one day, Julie raises = \frac{19}{6}

= $3.1666 ≈ $3.2

Time needed for Julie to reach her goal = \frac{1000}{3.2}

= 312.5 ≈ 313 days

Difference in the number of days to achieve their goals

= 334 - 313 = 21 days  

Hence, Julie will meet her goal first, 21 days prior to Mary.

Svet_ta [4.3K]12 days ago
3 0
Julie will achieve her objective first.
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Answer:

C and D

Step-by-step explanation:

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8 days ago
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A box has 14 camera of which 6 are refurbished and 8 are new. If four of these 14 cameras are selected at random without replace
Leona [4187]

Answer:

160/1001, 175/1001

Step-by-step explanation:

i) We calculate:

₈C₁ methods to select 1 new camera from a selection of 8

₆C₃ methods to select 3 refurbished cameras from a selection of 8

₁₄C₄ methods to select 4 cameras from the total of 14 cameras

The probability formula is:

P = ₈C₁ ₆C₃ / ₁₄C₄

P = 8×20 / 1001

P = 160 / 1001

P ≈ 0.160

ii) For at most one new camera, it means we want either one new camera or none at all. We've calculated the probability of selecting one new camera already. The probability of not selecting any new camera is equivalent to selecting 4 refurbished cameras:

P = ₆C₄ / ₁₄C₄

P = 15 / 1001

Therefore, the combined probability is:

P = 160/1001 + 15/1001

P = 175/1001

P ≈ 0.175

4 0
10 days ago
If the area of the vegetable garden is 170 square feet which equation could be of use to find the length of the tomato patch? 0=
Svet_ta [4341]

Answer:

The equation 0 = 3x² + 17x - 160 might be useful in determining the length.

Step-by-step explanation:

The area of the vegetable garden is specified as 170 ft².

Now, regarding the provided equations;

1) For 0 = 3x² + 2x + 180, applying the quadratic formula results in:

x = [-2 ± √(3² - 4(3 × 180)]/(2 × 3)

x = [-2 ± √(-2151)]/6

The square root value is negative, indicating no real solution for x.

Thus, this equation does not help find the length.

2) For the equation 0 = 3x² + 10x + 180, employing the quadratic formula, the square root value is also negative, hence there's no natural root for x. This means this equation can't be used to determine the length.

3) For 0 = 3x² + 17x - 160, the roots when using the quadratic formula yield -10.67 or 5. The value 5 is viable since it is a whole number. Considering the area is also a whole number, this equation can be applied to ascertain the length.

4) For 0 = 3x² - 160, simplifying gives;

3x² = 160

x² = 160/3

x = ±√(160/3)

x = ±7.303

Since the area is a whole number but this length isn't, this equation may not accurately determine the length.

5 0
15 days ago
If Sam has 6 different hats and 3 different scarves, how many different combinations could he wear
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18

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6 0
13 days ago
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2. Peter drew two rays, AC and AP with A as a common endpoint. Which of the following statements
PIT_PIT [3949]

The complete question reads:

Peter created two rays, AC and AP, sharing a common vertex at point A. Which of the following statements

might accurately describe Peter's drawing?

I. AC and AP are parallel.

II. PAC represents an angle.

III. AC and AP are at right angles.

A. I and II

B. II and III

C. I and III

D. I, II, and III

Answer:

Option B: II & III

Step-by-step explanation:

We know Peter has drawn rays AC and AP.

Since the point A is shared as the endpoint, it indicates an angular relationship at this common point.

This angle could potentially be 90°, suggesting that rays AC and AP may be perpendicular.

Thus, the valid statements that characterize his drawing are: II & III.

4 0
2 days ago
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