10. Which of these is not an HTTP verb? PUT AJAX GET DELETE

Refer to the explanation provided. In the online shopping software system, five actors can be identified: A Customer can perform actions such as exploring products and seeking product information. The interface allows for the creation of customer accounts facilitating purchases. Additionally, customers can browse items by using search categories or keywords, and they are able to order and make payments for their selected products. The payment system accepts two primary methods: credit card and PayPal. A Seller can list products in appropriate categories and create accounts to gain membership. An Administrator manages product listings and can modify existing categories or introduce new ones. Finally, the Site Manager has the capability to view different reports regarding customer orders, seller-added products, and user-created accounts.

Response:

#code (count_seq.py)

def count_seq():

   n='2'

   while True:

       yield int(n)

       next_value=''

       while len(n)>0:

           first=n[0]

           count=0

     

           while len(n)>0 and n[0]==first:

               count+=1

               n=n[1:]

           next_value+='{}{}'.format(count,first)

       n=next_value

if __name__ == '__main__':

   gen=count_seq()

   for i in range(10):

       print(next(gen))

Clarification:

• Begin with the number 2. Utilize a string for easier manipulation rather than integers.
• Engage in an infinite loop.
• Yield the current integer value of n.
• Continue looping until n becomes an empty string.
• Repeat as long as n has content and the first digit matches the leading digit.
• Concatenate the count and the first digit to form next_value.

Answer:

Step 1: Create a table reflecting the three potential scenarios and two possible outcomes. There should be a total of 8 distinct rules for the three varying conditions, structured similarly to the discount table shown here in the example: attached is the discount table

Step 2: The rules can now be made simpler by taking the following aspects into account:

a) When a consumer completes the survey form AND opts into the newsletter, according to Rules 1 and 2, they qualify for a discount if their order exceeds $100. This leads to two distinct rules being formulated while the third condition (order quantity) holds significance.

b) If the buyer fills out the survey form OR subscribes to the newsletter, as indicated by Laws 3, 4, 5, and 6, they will benefit from free shipping, regardless of the order amount. As a result, this situation can be divided into two individual rules, where at least one requirement is satisfied, but not both.

c) When a customer fails to meet any requirements, corresponding to Rules 7 and 8, the order value will not qualify for either free shipping or discount. This can be seen as a single law. The linked simplification table illustrates this.

Answer:

Coins c1 = new Coins (4, 3, 2, 1);

c1.bankValue();

c1.addQuarter();

c1.addQuarter();

c1.addDime();

c1.addDime();

c1.addPenny();

c1.bankCount();

c1.bankValue();

Explanation:

Answer:

I am crafting a Python function:

def angry_file_finder(filename): #function definition, this function takes the file name as input

with open(filename, "r") as read: #the open() function is employed to access the file in read mode

lines = read.readlines() #readlines() yields a list of all lines in the file

for line in lines: #iterates through every line of the file

if not '!' in line: #checks if a line lacks an exclamation mark

return False # returns False if a line does not include an exclamation point

return True # returns true if an exclamation mark is present in the line

print(angry_file_finder("file.txt")) invokes the angry_file_finder function by supplying a text file name to it

Explanation:

The angry_file_finder function accepts a filename as its parameter. It opens this file in read mode utilizing the open() method with "r". Then it reads every line using the readline() function. The loop checks each line for the presence of the "!" character. If any line in the file lacks the "!" character, the function returns false; otherwise, it returns true.

There is a more efficient way to write this function without using the readlines() method.

def angry_file_finder(filename):

with open(filename, "r") as file:

for line in file:

if '!' not in line:

return False

return True

print(angry_file_finder("file.txt"))

The revised method opens the file in reading mode and directly uses a for-loop to traverse through each line to search for the "!" character. In the for-loop, the condition checks if "!" is absent from any line in the text file. If it is missing, the function returns False; otherwise, it returns True. This approach is more efficient for locating a character in a file.