Distance formula:

5 units-4.5 units=0.5 units
Segment LM exceeds segment JK by 0.5 units.
Set G consists of: G={4, 8, 12, 16, 20, 24, 28, 32, 36,...} Set F represents the perfect squares: F={1, 4, 9, 16, 25, 36, 49, 64, 81, 100...} Within set F, the numbers 4, 16, 36, 64, and 100 are multiples of 4. The result is: {4, 16, 36, 64, 100}.
The options presented are:
(1) division property of equality
(2) factoring the binomial
(3) completing the square
(4) subtraction property of equality
Response: (2) factoring the binomial
Step 1: 
Step 2:![-c = a[x^2+\frac{b}{a} x]](https://tex.z-dn.net/?f=%20%20-c%20%3D%20a%5Bx%5E2%2B%5Cfrac%7Bb%7D%7Ba%7D%20x%5D%20%20%20)
In step 2, 'a' is extracted from
. Upon factoring out 'a', we divide all terms by 'a', resulting in
.
Step 2 involves the binomial factorization process.
The equation representing the circle centered at (-27, 120) that passes through the origin is:

Solution:
The general equation of a circle is expressed as:

Where,
(a, b) denotes the center of the circle
r signifies the radius
Given the center as (-27, 120)
Thus;
a = -27
b = 120
Considering it intersects the origin, meaning (x, y) = (0, 0)
Substituting (a, b) = (-27, 120) and (x, y) = (0, 0) into the equation

Input
= 15129 and (a, b) = (-27, 120) into the equation

Hence, the equation characterizing the circle is determined