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13 days ago

Can crushers help us recycle in a space efficient way which is good for saving the earth and for giving you more room in your ap

artment. Let us model the illustrated crusher as a planar mechanism that is subjected to the pushing force on the lower "L-shaped" handle, i.e. link CDE. Note that link CDE is one solid piece, pinned at D and E. Knowing that the orange horizontal member has a square peg at that slides vertically in the slot on the blue frame, that the can is centered under the pin at and that N, , , mm, mm, mm, and mm, determine the force magnitude in N exerted on the can from the mechanism. N

Engineering

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Your driver license will be _____ if you race another driver on a public road, commit a felony using a motor vehicle, or are fou

iogann1982 [368]

Hello there,

In this scenario, the driver's license has been both confiscated and suspended.

Therefore, the answer is: A)

Achievements.

6 0

3 months ago

Read 2 more answers

A 2.0-in-thick slab is 10.0 in wide and 12.0 ft long. Thickness is to be reduced in three steps in a hot rolling operation. Each

Mrrafil [318]

Answer:

L_f = 26.025 ft

v_f = 51.77 ft/min

Explanation:

Given:

- Initial slab thickness, t_o = 2 in

- Initial slab width, w_o = 10 in

- Initial slab length, L_o = 12.0 ft

- Thickness reduction each step, r = 75%

- Width increase each step, m = 3%

- Initial entry speed vi = 40 ft/min

- Roll speed remains constant

Required:

a) Length

b) Exit velocity

For the final slab

Solution:

- After three passes, the final thickness (t_f) is determined as:

t_f = ( r / 100 )^n * t_o

Where n signifies the number of passes.

t_f = ( 75 / 100 ) ^3 * ( 2.0 )

t_f = 0.844 in

- The final width after three passes is calculated as:

w_f = ( m / 100 + 1 )^n * w_o

Where n denotes the number of passes.

w_f = ( 3 / 100 + 1 ) ^3 * ( 10.0 )

w_f = 10.927 in

- Assuming there is no loss in material, the final length of the slab can be obtained:

t_o*w_o*L_o = t_f*w_f*L_f

L_f = ( 2 * 10 * 12 ) / ( 0.844 * 10.927 )

L_f = 26.025 ft

- The equation for volume rate can be applied since the roll speed stays the same. Thus, we equate the conditions before and after the third step:

t_i*w_i*v_i = t_f*w_f*v_f

Where v_i is the initial speed at entry:

v_f signifies the exit speed after the third step.

(0.75)^2 * 2 * (1.03)^2 * 10 * 40 = (0.844)*(10.927)*v_f

v_f = 51.77 ft/min

8 0

2 months ago

A cylindrical tank is 50 inches long, has a diameter of 16 inches and contains 1.65 lbm of water. Calculate the density of water

alex41 [359]

Answer:

0.285 lbm per cubic foot

Explanation:

Length of tank = 50 inches = 50/12 feet = 4.17 feet

Diameter of tank = 16 inches = 16/12 feet = 1.33 feet

Weight of water = 1.65 lbm

Density of water =?

We know the density of a substance is defined as

ρ = w/v

where ρ is the density in lbm per cubic foot

w is the weight in lbm

v is the volume in cubic feet

Volume of a cylinder = $\frac{\pi d^{2} l}{4}$

where d is diameter

l is the length

volume = $\frac{3.142*1.33^{2}* 4.17}{4}$ = 5.79 cubic feet

Hence, the density of water will be

ρ = w/v = 1.65/5.79 = 0.285 lbm per cubic foot

8 0

2 months ago