The question lacks clarity. The advantage of lifting with a lever is that it allows you to apply force in a more manageable direction and necessitates far less force to lift an object by balancing the torque exerted by it. For instance, if you aim to lift an object weighing 4N with a force of 2N, utilizing a class 2 lever while maintaining a distance ratio between the body and the force application point from the fulcrum of 1:2 is adequate. In any scenario, one should balance the torque to achieve the desired force.
Answer:
Please refer to the explanation
Explanation:
Race distance is 5km
Top speed = 45 yards
Converting yards to kilometers:
1km equals 1093.613 yards
x = 45 yards
(1093.613 * x) = 45
x = 45 / 1093.613
x = 0.0411480 km
Where x indicates the maximum distance he can sustain his highest speed in kilometers.
Thus, from the data available, we can determine that Lamar will not be able to maintain his maximum speed for the full 5km race, as he can only sustain it for 0.0411 kilometers.
Response:
The work performed by the particle traveling from x = 0 to x = 2 m totals 20 J.
Details:
The force impacting a particle, which is restricted to the x-axis, is expressed as follows:

We need to calculate the work done on a particle moving from x = 0.00 m to x = 2.00 m.
The formula for the work done by the particle is defined as:


Consequently, the work executed by the particle between x = 0 and x = 2 m amounts to 20 J. Thus, this is the solution sought.
<span> </span><span>When the net torque and moment of inertia are given, calculating becomes straightforward.
Using the equation torque = I * alpha, where I represents the moment of inertia and alpha is the angular acceleration.
Consequently, 0.098 / 0.000075 results in 1306.666... rad / s^2
While the angular acceleration stays the same, you can also determine the angular velocity at that instance, which is 21.36 rad / s.</span>