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kumpel
11 days ago
14

A hiker walks 9.4 miles at an angle of 60° south of west. Find the west and south components of the walk. Round your answers to

the nearest tenth. Ax = miles Ay = miles
Physics
2 answers:
Sav [2.2K]11 days ago
3 0
For this calculation, we apply our understanding of trigonometric functions related to a right triangle in order to determine the x and y components of the walk. We perform the following steps:

sin 60 = ax / 9.4
ax = 8.14

cos 60 = ay / 9.4
ay = 4.7
Ostrovityanka [2.2K]11 days ago
3 0

Solution:

Ax= -4.7

Ay= -8.1

Clarification:

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In a third class lever, the distance from the effort to the fulcrum is ____________ the distance from the load/resistance to the
serg [2593]
The full sentence states:
In a third class lever, the distance between the effort and the fulcrum is LESS than the distance between the load/resistance and the fulcrum.
In a third class lever, the fulcrum is positioned on one end of the effort, while the load/resistance is on the opposite side, placing the effort somewhere in between. Consequently, the distance from the effort to the fulcrum is less than that from the load to the fulcrum.
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In mammals, the weight of the heart is approximately 0.5% of the total body weight. Write a linear model that gives the heart we
Yuliya22 [2420]

Answer:

The typical weight of a human heart is approximately 0.93 lbs.

Explanation:

Based on this,

the heart's weight constitutes about 0.5% of total body mass.

Total human weight = 185 lbs

Let the entire body weight be represented as w and the heart's weight as w_{h}.

We aim to determine the heart's weight for a human

Using the provided information

w_{h}=0.5\times w

Where, h = heart weight

w = human weight

w_{h}=\dfrac{0.5}{100}\times 185

w_{h}=0.93\ lbs

The final weight of a human heart is 0.93 lbs.

8 0
1 month ago
In very cold weather, a significant mechanism for heat loss by the human body is energy expended in warming the air taken into t
ValentinkaMS [2425]
A) B) Explanation: Given: temperature of air, temperature of lungs, specific heat transferred from the lungs, specific heat of air, mass of 1 L air, breath rate. A) Calculate the amount of heat required to raise the air in the lungs to body temperature. B) Determine heat loss per hour.
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8 days ago
The position of an object is given by x = at3 - bt2 + ct,where a = 4.1 m/s3, b = 2.2 m/s2, c = 1.7 m/s, and x and t are in SI un
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Answer:

The response to your inquiry is: 15 m/s²

Explanation:

Equation    x = at³ - bt² + ct

a = 4.1 m/s³

b = 2.2 m/s²

c = 1.7 m/s

First we calculate x at t = 4.1 s

x = 4.1(4.1)³ - 2.2(4.1)² + 1.7(4.1)

x = 4.1(68.921) - 2.2(16.81) + 6.97

x = 282.58 - 36.98 + 6.98

x = 252.58 m

Now we calculate speed

v = x/t = 252.58/ 4.1 = 61.6 m/s

Finally

acceleration = v/t = 61.6/4.1 = 15 m/s²

6 0
21 day ago
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Answer:

I'm uncertain

Explanation:

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