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NISA
3 months ago
8

Two wires are made out of the same metal, but one wire is twice as long as the other wire. which wire will have the greatest ela

stic modulus? the shorter wire
Physics
1 answer:
serg [3.5K]3 months ago
7 0

The elastic modulus is solely reliant on the material type, which varies among different materials based on their physical characteristics. It does not rely on the wire's length, cross-sectional area, or the force applied to the wire. Therefore, wire length does not influence the elastic modulus. As both wires are crafted from the same metal, their elastic moduli will be identical.

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A student with a mass of 66.0 kg climbs a staircase in 44.0 s. If the distance between the base and the top of the staircase is
serg [3582]

power = 205.8 \: watt \\ solution \\ mass = 66 \: kg \\ time = 44 \: sec \\ distance = 14 \\ now \\ power = \frac{w}{t} \\ \: \: \: \: \: \: \: \: = \frac{f \times d}{t} \\ \: \: \: \: \: = \frac{m \times g \times d}{t} \\ \: \: \: \: \: \: = \frac{66 \times 9.8 \times 14}{44} \\ \: \: \: \: = \frac{9055.2}{44} \\ \: \: \: \: \: = 205.8 \: watt \\ hope \: it \: helps

4 0
3 months ago
A uniformly charged spherical droplet of mercury has electric potential Vbig throughout the droplet. The droplet then breaks int
kicyunya [3294]

Answer:

\frac{V_{big}}{V_{small}} = n^{2/3}

Explanation:

Let the charge on the large droplet be denoted as Q.

When the radius of the droplet is R, the electric potential for the larger droplet can be expressed as:

V_{big} = \frac{KQ}{R}

If it splits into n identical droplets, let the charge of each be "q" and their radius be "r".

Applying volume conservation gives us:

\frac{4}{3}\pi R^3 = n(\frac{4}{3}\pi r^3)

r = \frac{R}{n^{1/3}}

Now, the potential for the smaller droplets is given as:

V_{small} = \frac{kq}{r}

V_{small} = \frac{K(Q/n)}{\frac{R}{n^{1/3}}}

V_{small} = \frac{1}{n^{2/3}}\frac{KQ}{R}

\frac{V_{big}}{V_{small}} = n^{2/3}

7 0
3 months ago
Can pockets of vacuum persist in an ideal gas? Assume that a room is filled with air at 20∘C and that somehow a small spherical
kicyunya [3294]

Answer:

The time required is 20 μs

Explanation:

Here is the data provided:

temperature = 20°C  = 293 K

radius = 1 cm

atomic mass of air = 29 u

To determine

the duration for air to refill the vacuum space

solution:

We calculate the root mean square velocity of air particles. This can be expressed as:

\frac{1}{2}mv^2 = \frac{3}{2}RT

where m indicates mass, t is temperature, v is speed, and R is the ideal gas constant, which is approximately 8.3145 (kg·m²/s²)/K·mol.

v = \sqrt{\frac{3RT}{M} }............................1

v = \sqrt{\frac{3(8.314)293}{29*10{-3}kg} }

Resulting in v = 501.99 m/s.

<pNow, to cover the distance of 1 cm,<pThe duration needed for air is calculated as:

time taken = \frac{r}{v}

which gives us:

time taken = \frac{1*10^{-2}m}{501.99}

so, time taken = 19.92 × 10^{6} seconds = 20μs.

Thus, the required time is 20 μs.

3 0
4 months ago
In the past, salmon would swim more than 1130 km (700 mi) to spawn at the headwaters of the Salmon River in central Idaho. The t
Keith_Richards [3271]

Answer:

E_t_o_t_a_l=7.603MJ

Explanation:

The overall energy expenditure of the salmon, which corresponds to its swimming upstream effort, W, is linked to its specific mechanical power. Mechanical \ power calculated per unit mass can be derived from the following equation:

\frac{p}{m}=\frac{1}{m}|\frac{dW}{dt}|=2W/kg\\\frac{1}{2}|\frac{W}{22\times 24 \times 60\times 60}|=2\\\\W=7.603MJ

As a result, the total energy utilized during the 22-day journey is 7.603 MJ

6 0
3 months ago
A test car carrying a crash test dummy accelerates from 0 to 30 m/s and then crashes into a brick wall. Describe the direction o
Maru [3345]

Answer:

The direction in which a vehicle accelerates aligns with its velocity direction. However, the force of acceleration works against the car's speed.

Explanation:

The car’s initial acceleration can be found using:

v = v₀ + a t

a = (v-v₀) t

which assumes the initial speed is zero (v₀ = 0 m/s).

a = v / t

a = 300 / t

The acceleration vector matches the direction of the vehicle's movement.

Upon hitting the wall, a force is exerted in the reverse direction to halt the car, thus this acceleration opposes the vehicle’s speed. However, the module should be much greater since the stopping distance is minimal.

5 0
3 months ago
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