Sherwin manages Delaroy County Zoo. The following table shows a probability model for the number of visitors on a weekday.

Find the P-value in a test of the claim that the mean IQ score of acupuncturists is equal to 100, given that the test statisti

Leona [12618]

Answer:

P-value = 0.0455

Step-by-step explanation:

This inquiry focuses on calculating the P-value in a test.

Mathematically, we establish that;

P-value = 2 * P(Z > |z|)

Please refer to the attached document for a comprehensive resolution and step-by-step explanation

7 0

2 months ago

The ground-state wave function for a particle confined to a one-dimensional box of length L is Ψ=(2/L)^1/2 Sin(πx/L). Suppose th

AnnZ [12381]

Respuesta:

(a) 4.98x10⁻⁵

(b) 7.89x10⁻⁶

(c) 1.89x10⁻⁴

(d) 0.5

(e) 2.9x10⁻²

Explicación paso a paso:

La probabilidad (P) de encontrar la partícula está dada por:

$P=\int_{x_{1}}^{x_{2}}(\Psi\cdot \Psi) dx = \int_{x_{1}}^{x_{2}} ((2/L)^{1/2} Sin(\pi x/L))^{2}dx$

$P = \int_{x_{1}}^{x_{2}} (2/L) Sin^{2}(\pi x/L)dx$ (1)

La solución de la integral de la ecuación (1) es:

$P=\frac{2}{L} [\frac{X}{2} - \frac{Sin(2\pi x/L)}{4\pi /L}]|_{x_{1}}^{x_{2}}$

(a) La probabilidad de encontrar la partícula entre x = 4.95 nm y 5.05 nm es:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{4.95}^{5.05} = 4.98 \cdot 10^{-5}$

(b) La probabilidad de encontrar la partícula entre x = 1.95 nm y 2.05 nm es:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{1.95}^{2.05} = 7.89 \cdot 10^{-6}$

(c) La probabilidad de encontrar la partícula entre x = 9.90 nm y 10.00 nm es:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{9.90}^{10.00} = 1.89 \cdot 10^{-4}$

(d) La probabilidad de encontrar la partícula en la mitad derecha de la caja, es decir, entre x = 0 nm y 50 nm es:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{50.00} = 0.5$

(e) La probabilidad de encontrar la partícula en el tercio central de la caja, es decir, entre x = 0 nm y 100/6 nm es:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{16.7} = 2.9 \cdot 10^{-2}$

Espero que te ayude.

3 0

2 months ago

Suppose we pick three people at random. For each of the 2.32 The following questions, ignore the special case where someone migh

Inessa [12570]

Answer:

(a) 1 in 365 or 0.2740%

(b) 0.8227%

Step-by-step explanation:

(a) For the first person's birthday, the probability that the second person has the same birthday is 1 out of 365, so the chance that the first two share a birthday is:

$P = \frac{1}{365}=0.2740\%$

(b) There are four scenarios possible where at least two individuals share a birthday: first and second, first and third, second and third, all three sharing the same birthday. Hence, the probability that at least two share their birthdays is:

$P =3* \frac{1}{365}+ (\frac{1}{365})^2\\ P=0.8227\%$

7 0

3 months ago

The Community Relief Fund receives a large donation of $2800. The foundation agrees to spend the money on $20 school bags, $25 s

babunello [11817]

The question appears incomplete:

The Community Relief Fund has accepted a significant donation of $2800. The foundation intends to allocate funds for $20 school bags, $25 sweaters, and $5 books. They aim to procure 200 items to send to schools in areas impacted by earthquakes. They must order the same amount of books as the total number of school bags and sweaters combined. How many of each item should they procure?

Answer:

They need to procure 40 bags, 60 sweaters, and 100 books.

Step-by-step explanation:

Based on the information given, we can derive the following equations:

x+y+z=200 (1)

20x+25y+5z=2800 (2)

z=x+y (3), where:

x=amount of bags

y=amount of sweaters

z=amount of books

Now, substituting (3) in (1) and (2):

x+y+x+y=200

2x+2y=200 (4)

20x+25y+5(x+y)=2800

20x+25y+5x+5y=2800

25x+30y=2800 (5)

We obtain 2 equations:

2x+2y=200 (4)

25x+30y=2800 (5)

We can isolate x in (4):

2x=200-2y

x=100-y (6)

Next, we can plug (6) into (5):

25(100-y)+30y=2800

2500-25y+30y=2800

5y=2800-2500

y=300/5

y=60

Now, we can substitute the value of y in (6) to find x:

x=100-60

x=40

Finally, we can replace the values of x and y in (3) to find z:

z=40+60

z=100

Thus, it is concluded that they need to order 40 bags, 60 sweaters, and 100 books.

7 0

1 month ago