Giovanni orders a pastry from the bakery. The price of the pastry before tax is $4.50. Giovanni wants to know the total price in

Approximately 2, I believe... I calculated it to be around 2.10. 

Part 1) side 1=15'-7" side 2=20'-4" side 3=26'-2" To determine the total length of all three sides, add them together: total length=side 1+side 2 +side 3. By substituting, total length=15'-7"+20'-4"+26'-2" can be expressed as total length=(15'+20'+26')+(7"+4"+2"). This simplifies to total length=(61')+(13"). Keep in mind that 12"=1', so 13" can be expressed as 12"+1"=1'+1". By substituting again: total length=(61')+(1'+1") simplifies to total length=(62')+(1") which leads to 62'-1". Therefore, the total length of the three sides is 62'-1".

Given:
Two identical parallelograms total area = 9 1/3 yd²
Each parallelogram has height 1 1/3 yd

Area formula: area = base × height

Split the total area equally to find each parallelogram's area.

Convert 9 1/3: (9*3)+1 = 28/3

Divide by 2: 28/3 × 1/2 = 28/6 yd², which is 4 4/6 yd² → 4 2/3 yd²

So each parallelogram's area is 4 2/3 yd²

Set up base × 1 1/3 yd = 4 2/3 yd²

Convert and divide: 14/3 yd² ÷ 4/3 yd = base

Multiply: 14/3 × 3/4 = base
Compute: 14*3 / 3*4 = base
42 / 12 = base
Which simplifies to 3 6/12 yd = base
or 3 1/2 yd = base

a) Each parallelogram has a base of 3 1/2 yards
b) If the two parallelograms form a rectangle:
Rectangle area = length × width

Length = 3 1/2 yd × 2 = 7 yds
Width = 3 1/2 yds

Area = 7 yd × 3 1/2 yd
Area = 7 × 7/2 yd²
Area = 7*7 / 2 yd²
Area = 49 / 2 yd²
Area = 24 1/2 yd²

The maximum value of P is determined to be 33.

Step-by-step explanation: Start by graphing the constraints represented by the lines

5x + y = 16, which has intercepts at (16, 0) and (0, 16), and

2x + 3y = 22, with intercepts at (11, 0) and (0, ). The solutions to both sets of constraints lie beneath the lines. Solve the equations 5x + y = 16 and 2x + 3y = 22 simultaneously to find their intersection point at (2, 6).

The vertices of the feasible region are determined to be (0, 0), (0, 16), (2, 6), and (11, 0). Evaluate the objective function at each vertex.

At (0, 0), P = 0. At (0, 16), P = 32. At (2, 6), P = 18. Finally, at (11, 0), P = 33. Thus, the maximum P value occurs when x = 11 and y = 0.