Answer:
The likelihood that a failure will not take place within the next 30 months is 0.0454.
Step-by-step explanation:
We employ a Poisson distribution where:
t = time units
x = occurrences during t units
λ = average occurrences per unit of time
P(x;λt) = e raised to the power of (-λt) multiplied by λtˣ divided by x!
Here, λt equals 25.
x equals 30.
P(x= 30) = 25³⁰e⁻²⁵/ 30!
P (x= 30) = 8.67 E41 * 1.3887 E-11/30! (where E signifies exponent)
P (x=30) = 1.204 E31/30!
Utilizing a statistical calculator will yield:
P (x=30) = 0.0454
The probability that the next failure will not occur prior to 30 months is 0.0454.
Response:
$54
Detailed steps to explanation:
Initially
45 multiplied by.05 equals 2.25
Next
45 added to 2.25
Following that
45 multiplied by.15 equals 6.75
Finally
45 plus 2.25 plus 6.75
(a) For E based on d, the equation is E = 6500 - 50d
(b) After 30 days, the remaining excess will be 5000.
11,000 multiplied by 16% equals $1,750, which when multiplied by 4 gives a total of $7,040.
Therefore, after 4 years, the car's value is $11,000 - 7,040 = $3,960.