Assume that a fair die is rolled. The sample space is , 1, 2, 3, 4, 56, and all the outcomes are equally likely. Find P8. Expres

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10 days ago

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s your answer in exact form.

1 answer:

AnnZ [3.8K] · Answer 1 · 2026-02-23T09:30:07+03:00

Answer:

$P\left(8\right)=0$

Step-by-step explanation:

Assuming a fair die is rolled.

The sample space comprises 1, 2, 3, 4, 5, 6, with all results being equally probable.

Let X represent the collection of all outcomes. Let A represent a specific outcome.

<pThus, the probability of event A occurring is:

$P\left(A\right)=\frac{|A|}{|X|}$

Considering that the set of all possible outcomes for a singular die roll is:

$X=\left\{1,2,3,4,5,6\right\}$

Notably,

$|X|=6$

Here,

$|A|=0$ since 8 is not included in the sample space. Therefore, rolling an 8 is impossible within the defined outcomes.

<pThis leads to the conclusion that the probability is zero.

In other terms,

$P\left(A\right)=\frac{|A|}{|X|}$

$P\left(8\right)=\frac{0}{6}=0$

<pAs a result,

$P\left(8\right)=0$