C because a negative would turn into a positive.
$5,000.00 invested for a period of 6 years doubles to $10,000.00.
What is the interest rate?
You will need to apply logarithms:
<span>log(1 + rate) = {log(total) - log(Principal)} ÷ Years
</span>log(1 + rate) = <span>{log(10,000) - log(5,000)} ÷ 6
</span>log(1 + rate) = (4 - 3.6989700043) / 6
log(1 + rate) =
<span>
<span>
<span>
0.301029957 / 6
</span></span></span>log(1 + rate) =
<span>
<span>
<span>
0.0501716595
</span>
</span>
</span>
Next, raise 10 to the power of
<span>
<span>
<span>
0.0501716595
</span>
</span>
</span>
which results in
<span>
<span>
<span>
1.1224620317
</span>
</span>
</span>
This value represents 1 plus the interest rate, so the interest rate is
0.1224620317 or 12.24620317 percent.
This concludes Part ONE.
Now, onto Part TWO.
How many years does it take for $300 to increase to $9,600 at an annual rate of <span>12.24620317%?
You will use the following formula:
</span>(More logarithms involved).
Years = {log(total) - log(Principal)} ÷ log(1 + rate)
Years = {log(9,600) - log(300)} / log(<span>1.1224620317)
</span>Years = (3.982271233 - 2.4771212547) / 0.050171659518
<span><span><span>Years = 1.5051499783 /
</span>
</span>
</span>.050171659518
Years = 30
The volume of a cylinder can be determined using the formula pi*h*d^2/4, which leads us to V = pi*(39 mm)(39 mm)^2 / 4 = 46,589 mm^3. Dividing the mass of 1 kg by the volume of 46,589 mm^3 results in a density of 2.1464 x 10^-5 kg/mm^3. Typically, density is expressed in kg/m^3, so we convert this by multiplying by 1x10^9, yielding a density of 21,464 kg/m^3.
Answer:
The formula to determine the distance Jane's trainer bikes is
.
Detailed explanation:
A diagram has been included for clarity.
Known values:
Distance biked to the south = 16 miles
Distance ran west = 12 miles
We need to determine the distance covered by Jane's trainer.
Solution:
Let the biking distance be represented by 'x'.
We will assume it forms a right-angled triangle.
According to the Pythagorean theorem, it states that;
"The square of the hypotenuse is equal to the sum of the squares of the other two sides."
When set in equation form, this gives us;

Thus, the equation representing the distance biked by Jane's trainer is
.
Upon solving, we find;

Consequently, Jane's trainer covers a distance of 20 miles.