Ka, the acid dissociation constant, for an acid is 9 × 10^{−4} at room temperature. At this temperature, what is the approximate

A. 1.01 is the accurate result

Because

The formula used is Pv= nRT

P=1 atm

V= 22.4 L

N= x

R= 0.0821

T= 273 K (since it’s standard temperature)

Thus, (1)(22.4)=(x)(0.0821)(273)

X= 1.001

Answer:

Wood

Explanation:

Answer:

This is a satellite that gathers information on rainfall and snow.

• Its orbit spans 90 percent of the Earth's surface.

• The sensors detect microwaves.

Explanation:

Right on track