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vivado
13 days ago
11

What does it mean if Keq >> 1?

Chemistry
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Compared to a 26-gram sample of NaCl(s) at STP, a 52-gram sample of NaCl(s) at STP has(1) a different density(2) a different gra
KiRa [2933]
Choice (3) is correct: they exhibit the same chemical properties. Both samples are under identical conditions, so their densities remain unchanged. Gram-formula mass is an intrinsic property of the substance and does not vary. The volume would change if the mass changes.
6 0
1 month ago
A saturated solution of potassium iodide contains, in each 100 mL, 100 g of potassium iodide. The solubility of potassium iodide
KiRa [2933]

Answer:

The specific gravity of the saturated solution is 2

Explanation:

Specific gravity represents the ratio of the density of a solution, in this case, a saturated potassium iodide (KI) solution, to the density of water. Assuming the density of water is 1:

Specific gravity  = Density

Density itself is defined as the mass divided by volume.

In 100mL of water, the mass of dissolve-able KI is:

100mL * (1g KI / 0.7mL) = 143g of KI

This indicates that all 100g of KI dissolves (Mass solute)

With 100mL of water corresponding to a mass of 100g (Mass solvent)

The overall mass of the solution computes to 100g + 100g = 200g

In a volume of 100mL, the solution's density is:

200g / 100mL = 2g/mL.

Specific gravity is a dimensionless quantity, thus the specific gravity of the saturated solution is 2

5 0
1 month ago
41. A 13.0% solution of K2CO3 by mass has a density of 1.09 g/cm3. Calculate the molality of the solution.
lions [2927]

Answer:

The molality of the solution is 1.08 m.

Explanation:

First, determine the mass of the solvent.

A 13% solution by mass indicates that 13 grams are found in every 100 grams of solution.

Thus, solution mass = solute mass + solvent mass

100 g = 13 g + solvent mass

Therefore, solvent mass = 100 g - 13 g → 87 g

Next, we calculate the moles of solute (mass / molar mass):

13 g / 138.2 g/mol = 0.094 moles

Finally, to find the molality, which is the moles of solute per 1 kg of solvent (mol/kg), we convert the solvent mass to kg:

87 g. 1 kg / 1000 g = 0.087 kg

Then, molality → 0.094 mol / 0.087 kg = 1.08 m

5 0
2 months ago
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