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ELEN
2 days ago
12

What is the mass of 22.4 L of H2 at STP?

Chemistry
2 answers:
eduard [944]2 days ago
7 0

A. 1.01 is the accurate result

Because

The formula used is Pv= nRT

P=1 atm

V= 22.4 L

N= x

R= 0.0821

T= 273 K (since it’s standard temperature)

Thus, (1)(22.4)=(x)(0.0821)(273)

X= 1.001

KiRa [971]2 days ago
6 0

Answer: The correct choice is option (b).

Explanation:

STP refers to standard temperature and pressure. Under these conditions, pressure is set at 1 atm, volume at 22.4 L, and temperature at 298 K.

Consequently, by using the ideal gas equation, we can compute the number of moles as follows.

                             PV = nRT

                        1 atm \times 22.4 L = n \times 0.0832 Latm K^{-1}mol^{-1} \times 298K

                                 n = 0.903 mol

                                    ≈ 1 mol

Therefore, given that the molar mass of a hydrogen molecule is 2 g/mol, we can calculate the mass of H_{2} at STP as follows.

                 Number of moles = \frac{mass}{molar mass}

                       1 mol = \frac{mass}{2.02 g/mol}

                          mass = 2.02 g

Thus, we can conclude that the mass of 22.4 L of H2 at STP is 2.02 grams.

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Answer:

Complete Question:  

Equimolar quantities of CH3OH(l) and C2H5OH(l) are placed in separate 2.0 L containers that have been evacuated beforehand. Pressure gauges are attached to each container, and the temperature is maintained at 300 K. In both containers, liquid is consistently visible at the bottom. The varying pressure within the vessel that contains CH3OH(l) is illustrated below.

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