Use the graphing calculator to locate the solutions of this system of equations:

The solution to this inequality is.5>x

Try this method:
When a graph shifts right, replace 'x' with 'x' minus the number.
When it shifts down, subtract the number from 'y'.
So the final equation becomes: y = 4(x - 5)² - 18.
The answer is A.

Answer:

At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.

Step-by-step explanation:

A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.

The null and alternative hypotheses are:

The significance level is set at 0.10.

The sample mean recorded is 17, and the sample standard deviation is 5.37.

The degrees of freedom are calculated as df=(20-1)=19.

The t-statistic is:

The two-tailed P-value corresponding to t=1.67 is P=0.11132.

<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.

At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.

Response:

Step-by-step breakdown:

For the null hypothesis,

H0: p = 88

For the alternative hypothesis,

Ha: p < 88

In terms of population proportion, where the probability of success is p = 0.88

q represents the probability of failure = 1 - p

q = 1 - 0.88 = 0.12

Considering the sample,

Sample proportion, P = x/n

Where

x = number of successes = 21

n = total samples = 32

P = 21/32 = 0.66

Next, we determine the test statistic, which represents the z-score

z = (P - p)/√pq/n

z = (0.66 - 0.88)/√(0.88 × 0.12)/32 = - 3.83

The relevant p-value corresponds by referencing the normal distribution table for the area falling beneath the z-score. As a result,

P value = 0.00006

Organizing the data in increasing order to find the outlier and compute the mean

Detailed explanation:

The provided data consists of: [4, 1, 3, 10, 18, 12, 9, 4, 15, 16, 32]

Arranging it in ascending sequence

                               [1, 3, 4, 4, 9, 10, 12, 15, 16, 18, 32 ]

The outlier is identified as 32

Calculating the mean;

Mean=total of data set/quantity of data set

Total= 1 + 3+ 4+ 4+ 9+ 10+ 12+ 15+ 16+ 18+ 32=124

Quantity of data set=11

Mean=124/11=11.27