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AfilCa
10 days ago
14

What is the speed of a 48 kg dog running across a lawn with 216 J of energy?

Physics
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Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant
Yuliya22 [3333]

Answer:

v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s

Explanation:

In this scenario, we determine the initial velocity as follows:

v_i = 7 \frac{m}{s}

The final velocity in this instance can be expressed as:

v_f = 13 \frac{m}{s}

It is noted that transitioning from 7m/s to 13m/s takes 8 seconds. We can apply a specific kinematic equation to find the acceleration for the first part of the journey:

v_f = v_i +at

Solved for acceleration, we find:

a = \frac{v_f -v_i}{t} = \frac{13 m/s -7 m/s}{8 s}= 0.75 \frac{m}{s^2}

For the subsequent route, we assume constant acceleration and that the train continues for 16 seconds, beginning with an initial velocity of 13m/s from the previous segment, allowing us to calculate the final speed via the following formula:

v_f = v_ i +a t

Substituting into the equation yields:

v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s

5 0
3 months ago
Leading edge flaps can be used to decrease (or eliminate) the leading edge suction peak at a desired lift coefficient. When airf
kicyunya [3294]

Answer:

An examination is conducted to assess how basic thin airfoils perform in slightly supersonic flow conditions, utilizing the nonlinear transonic theory initially proposed by von Kármán[1]. Formulas for the pressure coefficient across an oblique shock and a Prandtl-Meyer expansion are devised based on a transonic similarity variable. Aerodynamic coefficients are computed in similarity form for flat plates and asymmetric wedge airfoils, and their graphical representations are created. Sample plots are provided for a flat plate and a particular asymmetric wedge, shown on conventional coordinate axes of Cl, Cd, and Cmc/4 in relation to angle of attack and Cl against Mach Number to showcase distinct characteristics of nonlinear flow.

Explanation:

5 0
1 month ago
A charged wire of negligible thickness has length 2L units and has a linear charge density λ. Consider the electric field E-vect
Softa [3030]

Answer:

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

Explanation:

Consider the following:

Length= 2L

Linear charge density=λ

Distance= d

K=1/(4πε)

The electric field measured at point P

E=2K\int_{0}^{L}\dfrac{\lambda }{r^2}dx\ sin\theta

sin\theta =\dfrac{d}{\sqrt{d^2+x^2}}

r^2=d^2+x^2

Thus,

E=2K\lambda d\int_{0}^{L}\dfrac{dx }{(x^2+d^2)^{\frac{3}{2}}}

Now, by applying integration to the equation above

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

4 0
3 months ago
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