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Ivan
15 days ago
12

Two 11.5-mg balls are connected by a 28.9-cm-long insulating rod of negligible mass. One ball has a charge of +q and the other h

as a charge of −q. The system is placed in a 592 N/C uniform electric field. Initially the system is at rest and makes an angle α= 58.9° with respect to the field. It is then released, and when it is momentarily aligned with the electric field, its kinetic energy is 4.86 mJ. What is the magnitude of q?
Physics
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A food item that is left out of the refrigerator turns brown and forms bubbles and gas. What are the signs that this is a chemic
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A kinesin that is transporting a secretory vesicle uses approximately 80 ATP molecules/s. Each ATP provides a kinesin molecule w
inna [3103]

Answer:

The force is  F = 8*10^{-12} \ N

Explanation:

According to the inquiry, we understand that

     The rate at which ATP molecules are utilized is R = 80 ATP/ s

       The energy yielded by a single ATP molecule is  E_{ATP} = 0.8 * 10^{-19} J

       The kinesin's velocity is  v = 800 nm/s = 800*10^{-9} m/s

The power generated by the ATP in one second can be expressed mathematically as

       P = E_{ATP} * R

After substituting the values

       P = 80 * 0.8*10^{-19 }

       P = 6.4 *10^{-18}J/s

Now this power can be represented mathematically as

       P = F * v

Where  F indicates the force exerted by the kinesin

Therefore

          F = \frac{P}{v}

after substituting input values

            F = \frac{6.4*0^{-18}}{800 *10^{-9}}

           F = 8*10^{-12} \ N

7 0
2 months ago
A car in a movie moving at 20 m/s flies off a cliff that is 74.3m tall. How long is the car in the air for and how far does the
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We apply the formula S=½gt², where S represents the vertical distance of 74.3m, and g is the acceleration due to gravity valued at 9.8 m/s². Therefore, t=√(2S/g)=3.884 seconds. Consequently, the car remains airborne for around 3.894 seconds. Its horizontal journey is vt=20×3.894=77.88m.
4 0
1 month ago
A charge of uniform volume density (40 nC/m3) fills a cube with 8.0-cm edges. What is the total electric flux through the surfac
Keith_Richards [3271]

Answer:

The flux across the cube's surface is 2.314\ Nm^{2}/C.

Solution:

According to the details provided:

Cube edge length, a = 8.0 cm = 8.0\times 10^{- 2}\ m.

Volume charge density, \rho_{v} = 40 nC/m^{3} = 40\times {- 9}\ C/m^{3}.

Now,

To find the electric flux:

\phi = \frac{q}{\epsilon_{o}}

where

\phi = electric flux

\epsilon_{o} = 8.85\times 10^{- 12}\ F/m = permittivity of vacuum.

The volume charge density for this scenario is described by:

\rho_{v} = \frac{Total\ charge, q}{Volume of cube, V}

Cube volume, V = a^{3}.

Thus,

V = (8.0\times 10^{- 2})^{3} = 5.12\times 10^{- 4}\ m^{3}.

The total charge can be derived from equation (2):

q = \rho_{v}V = 40\times {- 9}\times 5.12\times 10^{- 4}.

q = 2.048\times 10^{-11}\ F = 20.48\ pF.

Now, insert the value of 'q' into equation (1):

\phi = \frac{2.048\times 10^{-11}}{8.85\times 10^{- 12}} = 2.314\ Nm^{2}/C.

5 0
2 months ago
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