Response:
The investment's value after 3 years will be £11,904
Step-by-step explanation:
sarah invests £9600 with an 8% simple interest rate per annum
Duration is 3 years
Formula for simple interest
I = P*n* r
P is the initial investment= 9600
r signifies interest rate = 8% = 0.08
n = duration in years = 3
Now, we can calculate the interest using the formula
I = 9600 * 0.08 * 3= 2304
The interest accrued totals 2,304
Now, we combine the interest with the initial investment to find the investment's total value after 3 years
9600 + 2304= 11904
Answer:
Refer to the attached document for the complete question
Step-by-step explanation:
Given that,
y=Cos(kt)
We are looking for the value of k that satisfies 4y''=-25y
Let’s find y' and y''
y=Cos(kt)
y'=-kSin(kt)
y''=-k²Cos(kt)
Substituting this back into 4y''=-25y
4(-k²Cos(kt))=-25Cos(kt)
-4k²Cos(kt)=-25Cos(kt)
Dividing through by Cos(kt) under the assumption that Cos(kt) is not zero
-4k²=-25
k²=-25/-4
k²=25/4
Thus, k=√(25/4)
k= ± 5/2
b. Assuming we need to use this
y=ASin(kt)+BCos(kt)
Since k= ± 5/2
y=A•Sin(±5/2t)+ B•Cos(±5/2t)
y'=(±5/2)ACos(±5/2t)-(±5/2)BSin(±5/2t)
y''=-25/4ASin(±5/2t)-25/4BCos(±5/2t
Then, substituting this into our equation can check if it holds true for y=ASin(kt)+BCos(kt)
4y''=-25y
For 4y''
4(-25/4ASin(±5/2t)-25/4BCos(±5/2t))
-25A•Sin(±5/2t)-25B•Cos(±5/2t.
We see that, 4y'' is indeed equal to -25y, confirming that y=Cos(kt) resolves into y=ASin(kt)+BCos(kt)
Answer:
All prime numbers under its square root.
Step-by-step explanation:
