There are 4 roads leading from Bluffton to Hardeeville, 10 roads leading from Hardeeville to Savannah, and 5 roads leading from

Savannah to Macon. How many ways are there to get from Bluffton to Macon

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Translate into an algebraic expression and simplify if possible. C It would take Maya x minutes to rake the leaves and Carla y m

lawyer [12517]

Answer:

together they rake $\frac{y+x}{xy}$ leaves in one minute.

Step-by-step explanation:

If Maya takes x minutes to rake, then in one minute, she rakes $\frac{1}{x}$ leaves.

For Carla, if her raking takes y minutes, in one minute she rakes $\frac{1}{y}$ leaves.

Thus, to find the amount they work together in one minute, we add both of their contributions for that minute, resulting in: $\frac{1}{x}+ \frac{1}{y}$

Finally, simplifying this expression gives:

$\frac{1}{x}+ \frac{1}{y} =\frac{y+x}{xy}$

As a result, they collectively rake $\frac{y+x}{xy}$ leaves in a minute.

8 0

3 months ago

There are seven boys and five girls in a class. The teacher randomly selects three different students to answer questions. The f

Svet_ta [12734]

The likelihood of selecting one girl is calculated as $\frac{5}{12}$ . This is based on having 5 girls within a total of 12 students, and the probability of an event can be expressed as: $\frac{\text{# of things you want}}{\text{# of things are possible}}$ .

Using the same reasoning, for the next student, we have reduced the number of students by 1, leading to 11 possible outcomes instead of 12, giving us: $\frac{7}{11}$ , which represents the probability of selecting a boy as the second choice.

Lastly, the probability of choosing a girl for the third selection follows the same logic and is given as: $\frac{4}{10}$ .

However, we must combine these individual probabilities to determine the likelihood of this specific sequence of selections occurring:

$\frac{5}{12}*\frac{7}{11}*\frac{4}{10}=\frac{140}{1320}$

This simplifies to:

$\frac{7}{66}$

4 0

3 months ago

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