Driving at a constant speed, Reggie travels 300 kilometers in 1 hour. What is Reggie’s speed in kilometers per hour? Reggie driv

The factors of 36 include: 1, 2, 3, 4, 6, 9, 12, 18, 36.
For 34, the factors are: 1, 2, 17, 34.
The factors of 22 are: 1, 2, 11, 22.
The greatest common factor (GCF) is 2.

Answer:

Step-by-step explanation:

Hello!

The monitoring system alerts the driver when the vehicle's tire pressure drops to 28% below the set target pressure.

Let X be: the target tire pressure for a particular vehicle (measured in pounds per square inch)

a)

X= 28 psi

When the monitoring device alerts at a pressure of 28% below the designated target: X-0.28X

Initially, calculate 28% of 28 psi.

28*0.28= 7.84

Next, subtract this 28% calculation from the target pressure:

28 - 7.84= 20.16

The TPMS will activate its warning at 20.16 psi.

b)

Assuming X~N(μ;σ²)

μ= 28 psi (as the average indicates accurate targeting, this represents the expected tire pressure)

σ= 3 psi

P(X≤20.16)

The standard normal distribution is available in tables. To convert any random variable X with a normal distribution, one subtracts its mean and divides by the standard deviation.

To compute the desired probabilities, the variable value undergoes transformation to fit the standard normal distribution Z, after which standard normal tables are referenced to find probabilities.

Z= (X-μ)/σ= (20.16-28)/3= -2.61

Now locate the probability corresponding to the Z value using the Z-table. Given the negative result, refer to the left entry; in the first column, find the integer and first decimal for -2.6- and in the first row locate the second decimal for -.-1

The probability link for -2.61 is:

P(Z≤-2.61)= 0.005

c)

The task is to determine the likelihood of encountering a tire at random within the recommended inflation range, expressed as:

P(30≤X≤26)= P(X≤30)-P(X≤26)

Determine both Z values:

Z= (30-28)/3= 0.67

Z= (26-28)/3= -0.67

P(Z≤0.67)-P(Z≤-0.67)= 0.749 - 0.251= 0.498

<pThe calculated probability of a tire being inflated within the suggested range is 0.498.

I hope this information is useful!

Total students enrolled = 18 + 7 = 25

Mean height of these 25 students = 105 - 5 = 100 cm

Total height of all students combined = 100 x 25 = 2500cm

Final answer: 2500cm

Answer:

B. $0.30

Detailed explanation:

1 candy bar equals $0.20

3 candy bars equal $0.50

To find the solution, let's calculate for both options:

If you buy each candy bar separately, the cost is $0.20 each. For 9, it would be:

9 x 0.20 = $1.80

If you purchase 3 at a time, they are $0.50 each set. Dividing 9 by 3, then multiplying by 0.50 gives:

9/3 = 3

3 x 0.50 = $1.50

Now calculate the difference between the individual total and the pack total:

$1.80 - $1.50 = $0.30

B. $0.30 is your final answer.

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Solution:

Let x be the distance in miles from the house to the theater.

Total time taken for the trip

Then average speed

Terrence walks at a speed of 2 miles per hour to the theater and returns home at 40 miles per hour.

Thus, Average Speed mi/hr

Both average speeds must be equivalent. Hence, we can express this as:

Consequently, the distance from home is 13.125 miles.