To obtain a complete response, the diagram would be essential. However, to approximate the solution, I'd calculate the distances from her home to her school and combine that with the stretch from school to work, and finally, from work back home. If there’s no information regarding the distance from work to home, I’d simply double the traveled distance already accounted for.
The result is 3.6y. By multiplying 0.3 by 12, we arrive at 3.6, and we include the variable y.
Marco requires $420 to purchase a new smartphone along with accessories. The equation 75-495=420 demonstrates this while adding $75 to $420 yields a total of $495.
Response:
The data shows skewness, with the minimum amount of crackers in a pack being 7
Detailed explanation:
Hello,
Firstly, the question lacks completeness due to missing information from the box plot, which I have provided to assist you in answering your inquiry.
Considering the details from the attached image, a symmetric distribution would be centered evenly, but that is not the case here.
The image indicates a positive skew, with the lowest count recorded as 7.
Answer:
Option 1 is valid, which entails 2 hours of walking and 12 hours of running.
Step-by-step explanation:
The equations provided are:
3w + 6r ≥ 36
3w + 6r ≤ 90
We'll assess which options comply with these equations.
1) 2 hours walking; 12 hours running
w = 2 and r = 12
3w + 6r ≥ 36
3(2) + 6(12) ≥ 36
6+72 ≥ 36
78 ≥ 36
3w + 6r ≤ 90
3(2) + 6(12) ≤ 90
6+72 ≤ 90
78 ≤ 90
Both equations are satisfied. Option 1 is valid.
2) 4 hours walking; 3 hours running
w = 4 and r = 3
3w + 6r ≥ 36
3(4) + 6(3) ≥ 36
12+18 ≥ 36
30 ≥ 36 (this does not hold since 30 < 36)
3w + 6r ≤ 90
3(4) + 6(3) ≤ 90
12+18 ≤ 90
30 ≤ 90
Thus, Option 2 is invalid.
3) 9 hours running; 12 hours walking
w = 9 and r = 12
3w + 6r ≥ 36
3(9) + 6(12) ≥ 36
27+72 ≥ 36
99 ≥ 36
3w + 6r ≤ 90
3(9) + 6(12) ≤ 90
27+72 ≤ 90
99 ≤ 90 (this does not hold since 99 > 90)
Option 3 is invalid.
4) 12 hours walking; 10 hours running
w = 12 and r = 10
3w + 6r ≥ 36
3(12) + 6(10) ≥ 36
36+60 ≥ 36
96 ≥ 36
3w + 6r ≤ 90
3(12) + 6(10) ≤ 90
36 + 60 ≤ 90
96 ≤ 90 (this does not hold since 96 > 90)
So, Option 4 is invalid.
