Use integers that are that are closest to the number in the middle. <

A software engineer creates a LAN game where an 8 digit code made up of 1,2,3,4,5,6,7,8 has to be decided on, universal code . T

PIT_PIT [12445]

Respuesta:

0.0143 = 1.43% de probabilidad de que los primeros 4 dígitos del código sean números pares.

Explicación paso a paso:

Arreglos de elementos n:

El número de arreglos posibles de n elementos se determina por:

$A_{n} = n!$

Probabilidad:

La probabilidad se calcula dividiendo el número de resultados deseados por el número total de resultados.

En esta pregunta:

Resultados deseados:

Los primeros cuatro dígitos son pares (2, 4, 6 y 8 son pares, así que se consideran 4 elementos).

Los últimos cuatro dígitos son impares (1, 3, 5 y 7 son impares, por lo que los últimos cuatro elementos son también arreglos de 4 elementos). Entonces

$D = 4!*4! = 24*24 = 576$

Resultados totales:

Arreglos de 8 dígitos. Así que

$T = A_{8} = 8! = 40320$

Probabilidad:

$p = \frac{D}{T} = \frac{576}{40320} = 0.0143$

0.0143 = 1.43% de probabilidad de que los primeros 4 dígitos del código sean números pares.

3 0

2 months ago

Angie baked 100 cookies and 20 brownies. She wants to split them into equal groups for the big sale. Each group must have the

zzz [12365]

Avoid repeating the question as it can be perplexing.

Given 100 cookies and 20 brownies,
What is the highest number you can divide them equally by?

To find the greatest common factor,
Factor them:
100 = 2*2*5*5
20 = 2*2*5
Thus, the greatest common factor, which is shared between them, is 2*2*5 or 20.

Calculating further, 100/20=5
20/20=1

This means there are 20 groups, each containing 5 cookies and 1 brownie.

20 groups

7 0

3 months ago

Which statement is true about the discontinuities of the function f(x)? F (x) = StartFraction x minus 5 Over 3 x squared minus 1

AnnZ [12381]

Question:

Which statement is accurate concerning the function’s discontinuities $f(x) = \frac{x-5}{3x^2-17x-28}$

A) There are gaps at x = 7 and.

B) Asymptotes exist at x = 7 and.

C) Asymptotes exist at x = –7 and.

D) Gaps are present at (–7, 0) and.

Answer:

B) Asymptotes exist at x = 7 and $(x = \frac{-4}{3})$

Step-by-step explanation:

Given:

$f(x) = \frac{x-5}{3x^2-17x-28}$

Goal:

Identify the correct statement

$f(x) = \frac{x-5}{3x^2-17x-28}$

We need to factor the denominator first.

$f(x) = \frac{x-5}{(3x+4)(x-7)}$

To express x in terms of (3x+4) and (x-7):

3x + 4 =

3x = -4

Divide both sides by 3:

$x = \frac{-4}{3}$

x - 7

x = 7

Next, evaluate the limit when $(x = \frac{-4}{3})$ and at (x = 7)

lim f(x) as $(x = \frac{-4}{3})$ = ±∞

lim f(x) as (x=7) = ±∞

Since both scenarios result in the denominator approaching zero, they represent asymptotes.

Thus, asymptotes are found at $(x = \frac{-4}{3})$ and x=7

Option B is determined to be correct

6 0

3 months ago

2 box plots. The number line goes from 175 to 450. For resort A, the whiskers range from 175 to 375, and the box ranges from 250

lawyer [12517]

Answer: 275 for one, and 325 for two

Step-by-step explanation:

I completed the calculations

3 0

2 months ago

Read 2 more answers

Use integers that are that are closest to the number in the middle. < - v119