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Paraphin
3 months ago
12

Angie baked 100 cookies and 20 brownies. She wants to  split them into equal groups  for the big sale. Each group must have the

same number of cookies and brownies, with none left over. What is the greatest number of groups she can make? Angie baked 100 cookies and 20 brownies. She wants to  split them into equal groups  for the big sale. Each group must have the same number of cookies and brownies, with none left over. What is the greatest number of groups she can make? Angie baked 100 cookies and 20 brownies. She wants to  split them into equal groups  for the big sale. Each group must have the same number of cookies and brownies, with none left over. What is the greatest number of groups she can make? 
Mathematics
1 answer:
zzz [12.3K]3 months ago
7 0
Avoid repeating the question as it can be perplexing.

Given 100 cookies and 20 brownies,
What is the highest number you can divide them equally by?

To find the greatest common factor,
Factor them:
100 = 2*2*5*5
20 = 2*2*5
Thus, the greatest common factor, which is shared between them, is 2*2*5 or 20.

Calculating further, 100/20=5
20/20=1

This means there are 20 groups, each containing 5 cookies and 1 brownie.


20 groups
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The chance of completing the entire package installation in under 12 minutes is 0.1271.

Step-by-step explanation:

We define X as a normal distribution representing the time taken in seconds to install the software. According to the Central Limit Theorem, X is approximately normal, where the mean is 15 and variance is 15, giving a standard deviation of √15 = 3.873.

To find the probability of the total installation lasting less than 12 minutes, which equals 720 seconds, each installation should average under 720/68 = 10.5882 seconds. Thus, we seek the probability that X is less than 10.5882. To do this, we will apply W, the standard deviation value of X, calculated via the formula provided.

Utilizing \phi, we reference the cumulative distribution function of the standard normal variable W, with values found in the attached file.

P(X < 10.5882) = P(\frac{X-15}{3.873} < \frac{10.5882-15}{3.873}) = P(W < -1,14)

Given the symmetry of the standard normal distribution density function, we ascertain \phi(-1.14) = 1-\phi(1.14) = 1-0.8729 = 0.1271.

Consequently, the probability that the installation process for the entire package is completed within 12 minutes is 0.1271.

Download pdf
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