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Paraphin
2 days ago
12

Angie baked 100 cookies and 20 brownies. She wants to  split them into equal groups  for the big sale. Each group must have the

same number of cookies and brownies, with none left over. What is the greatest number of groups she can make? Angie baked 100 cookies and 20 brownies. She wants to  split them into equal groups  for the big sale. Each group must have the same number of cookies and brownies, with none left over. What is the greatest number of groups she can make? Angie baked 100 cookies and 20 brownies. She wants to  split them into equal groups  for the big sale. Each group must have the same number of cookies and brownies, with none left over. What is the greatest number of groups she can make? 
Mathematics
1 answer:
zzz [4K]2 days ago
7 0
Avoid repeating the question as it can be perplexing.

Given 100 cookies and 20 brownies,
What is the highest number you can divide them equally by?

To find the greatest common factor,
Factor them:
100 = 2*2*5*5
20 = 2*2*5
Thus, the greatest common factor, which is shared between them, is 2*2*5 or 20.

Calculating further, 100/20=5
20/20=1

This means there are 20 groups, each containing 5 cookies and 1 brownie.


20 groups
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12x+7<−11 AND5x−8≥4012
Svet_ta [4321]

Answer:

No solution

Step-by-step explanation:

Given: 12x+7 and  5x-8\geq 40

Handle each inequality separately.

12x+7              Utilizing the subtraction property of inequalities

12x

12x

x

x

and

5x-8\geq 40               Utilizing the addition property of inequalities

5x\geq 40+8

5x\geq 48

x\geq \dfrac{48}{5}

Thus, the solution to the combined inequality is the overlap of both solutions.

Refer to the attached image for the number line representation.

No solution

8 0
11 days ago
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The steps to derive the quadratic formula are shown below: Step 1 ax2 + bx + c = 0 Step 2 ax2 + bx = − c Step 3 x2 + b over a ti
PIT_PIT [3919]

Answer:

x + \frac{b}{2a} = \frac{+/ - \sqrt{b^2-4ac} }{2a}

Step-by-step explanation:

Step 1:

ax^2+bx+c = 0

Step 2:

ax^2+bx = -c

Step 3:

\frac{ax^2+bx}{a} = \frac{-c}{a}

Step 4:

To complete the square, add \frac{b^2}{4a^2} to both sides.

x^2 + \frac{bx}{a} + \frac{b^2}{4a^2} = \frac{-c}{a} + \frac{b^2}{4a^2}

Step 5:

x^2 + \frac{bx}{a} + \frac{b^2}{4a^2} = \frac{-4ac+b^2}{4a^2}

Step 6:

Taking square roots on both sides.

x + \frac{b}{2a} = \frac{+/ - \sqrt{b^2-4ac} }{2a}

3 0
1 day ago
Un globo vuela entre dos ciudades A y B, que distan entre sí 1.500 m. Los tripulantes del globo ven la ciudad A con un ángulo de
Inessa [3907]

Respuesta:

La altitud del globo por encima del nivel del suelo es de 449,6 metros.

Explicación paso a paso:

El enunciado no está completo. El texto completo es: "Un globo se desplaza entre las ciudades A y B, que se encuentran a 1.500 m de distancia. Los ocupantes del globo observan la ciudad A con un ángulo de depresión de 27°, mientras que, para la ciudad B, el ángulo es de 36°. ¿Cuál es la altura aproximada del globo con respecto al suelo?"

El diagrama que ilustra esta situación está en el archivo adjunto. Para calcular la altura del globo, se pueden emplear las funciones trigonométricas, siendo recomendable hacer uso de la función tangente para los ángulos de depresión mencionados:

Ciudad A

\tan 27^{\circ} = \frac{h}{1500\,m-x}

0,510 = \frac{h}{1500\,m-x}

Ciudad B

\tan 36^{\circ} = \frac{h}{x}

0,727 = \frac{h}{x}

Donde h y x representan la altura desde el suelo y la distancia horizontal desde la ciudad A.

Luego, se igualan las alturas en ambas ecuaciones para calcular la distancia horizontal del globo en relación a la ciudad A:

0,727\cdot x = 0,510\cdot (1500\,m-x)

1,237\cdot x = 765\,m

x = 618,432\,m

Por último, la altura del globo sobre el suelo se calcula como:

h = 0,727\cdot x

h = 0,727\cdot (618,432\,m)

h = 449,600\,m

La altura del globo respecto al nivel del suelo es 449,6 metros.

6 0
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lawyer [4008]

Answer: 470.85 gallons

Step-by-step explanation:

12.9 gal/min multiplied by 36.5 min equals 470.85 gal

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THE CIRCLE EQUATION: (x - h)² + (y - k)² = r²


= (x + 1)² + (y - 4)² = 3
3 0
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