Which statement is true about the discontinuities of the function f(x)? F (x) = StartFraction x minus 5 Over 3 x squared minus 1

Question

3 days ago

14

7 x minus 28 EndFraction

1 answer:

AnnZ [3.8K] · Answer 1 · 2026-03-02T02:23:20+03:00

Question:

Which statement is accurate concerning the function’s discontinuities $f(x) = \frac{x-5}{3x^2-17x-28}$

A) There are gaps at x = 7 and.

B) Asymptotes exist at x = 7 and.

C) Asymptotes exist at x = –7 and.

D) Gaps are present at (–7, 0) and.

Answer:

B) Asymptotes exist at x = 7 and $(x = \frac{-4}{3})$

Step-by-step explanation:

Given:

$f(x) = \frac{x-5}{3x^2-17x-28}$

Goal:

Identify the correct statement

$f(x) = \frac{x-5}{3x^2-17x-28}$

We need to factor the denominator first.

$f(x) = \frac{x-5}{(3x+4)(x-7)}$

To express x in terms of (3x+4) and (x-7):

3x + 4 =

3x = -4

Divide both sides by 3:

$x = \frac{-4}{3}$

x - 7

x = 7

Next, evaluate the limit when $(x = \frac{-4}{3})$ and at (x = 7)

lim f(x) as $(x = \frac{-4}{3})$ = ±∞

lim f(x) as (x=7) = ±∞

Since both scenarios result in the denominator approaching zero, they represent asymptotes.

Thus, asymptotes are found at $(x = \frac{-4}{3})$ and x=7

Option B is determined to be correct