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olga2289
16 days ago
10

If r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (StartFraction r Over s EndFraction) (6)?

Mathematics
1 answer:
tester [3.9K]16 days ago
5 0

Answer:

\dfrac{r}{s}(6)=\dfrac{3(6)-1}{2(6)+1}

Detailed explanation:

For any two functions f(x) and g(x), we have

\dfrac{f}{g}(x)=\dfrac{f(x)}{g(x)}

Given the functions: r(x)=3x-1 and s(x)=2x+1

Therefore, \dfrac{r}{s}(x)=\dfrac{r(x)}{s(x)}

\Rightarrow\ \dfrac{r}{s}(x)=\dfrac{3x-1}{2x+1}

Evaluating at x = 6, we have

\dfrac{r}{s}(6)=\dfrac{3(6)-1}{2(6)+1}

This expression corresponds to \dfrac{r}{s}(6)=\dfrac{3(6)-1}{2(6)+1}

Simplifying further, the result is \dfrac{r}{s}(6)=\dfrac{18-1}{12+1}=\dfrac{17}{13}

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