An electrical short cuts off all power to a submersible diving vehicle when it is a distance of 28 m below the surface of the oc
1 answer:
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Refer to the diagram below.
Ignoring air resistance, use gravitational acceleration g = 9.8 m/s².
The pole vaulter drops with an initial vertical speed u = 0.
At impact with the pad, velocity v satisfies:
v² = 2 × (9.8 m/s²) × (4.2 m) = 82.32 (m/s)²
v = 9.037 m/s
As the pad compresses by 0.5 m to bring the vaulter to rest,
let the average acceleration (deceleration) be a m/s². Then:
0 = (9.037 m/s)² + 2 × a × 0.5 m
Solving for a gives:
a = - 82.32 / (2 × 0.5) = -82 m/s²
Thus, the deceleration magnitude is 82 m/s².
Ignoring air resistance, use gravitational acceleration g = 9.8 m/s².
The pole vaulter drops with an initial vertical speed u = 0.
At impact with the pad, velocity v satisfies:
v² = 2 × (9.8 m/s²) × (4.2 m) = 82.32 (m/s)²
v = 9.037 m/s
As the pad compresses by 0.5 m to bring the vaulter to rest,
let the average acceleration (deceleration) be a m/s². Then:
0 = (9.037 m/s)² + 2 × a × 0.5 m
Solving for a gives:
a = - 82.32 / (2 × 0.5) = -82 m/s²
Thus, the deceleration magnitude is 82 m/s².
Answer:
2.87 m
Explanation:
Given parameters:
Mass of the ball (m) = 60 g = 0.06 kg
Height of the tube (h) = 0.70 m
Force applied on the ball by compressed air (F) = 3.0 N
Initial velocity of the ball (u) = 0 m/s (Assumed)
Final velocity of the ball at the tube's exit (v) =?
Acceleration of the ball (a) =?
The ball's weight is derived from multiplying mass and gravity. Therefore,
Weight (W) =
Thus, the total force acting on the ball equals the net of upward force minus the weight.
Net force = Air force - Weight
According to Newton's second law, net force equals the mass multiplied by acceleration.
Acceleration (a) is calculated as 40.2 m/s².
Using the motion equation, we find:
Let’s denote the maximum height achieved as 'H'.
Next, we apply the principle of energy conservation from the pipe's peak to the maximum height.
A decrease in kinetic energy equals an increase in potential energy.
Substituting the values, we solve for 'H', yielding:
Hence, the ball ascends to a height of 2.87 m above the top of the tube.
Answer:
Electric flux is calculated as
Explanation:
We start with the given parameters:
The electric field impacting the circular surface is
Our objective is to ascertain the electric flux passing through a circular region with a radius of 1.83 m situated in the xy-plane. The area vector is oriented in the z direction. The formula for electric flux is expressed as:
Applying properties of the dot product, we calculate the electric flux as:
Consequently, the electric flux for the circular area is . Thus, this represents the required answer.