<span>this might be useful
Regarding the field, the two charges placed opposite cancel each other out!
Therefore, E = kQ / d² = k * Q / (d/√2)² = 2*k*Q / d² ◄
given k = 8.99×10^9 N·m²/C²,
E = 1.789×10¹⁰ N·m²/C² * Q / d² </span>
Answer:
The correct response is:
1. KE Increases, PE Increases, ME Increases.
Explanation:
In this context, kinetic energy refers to the energy associated with an object's motion. Kinetic energy can be defined as the energy required to accelerate a mass from rest to a specified velocity, which it maintains once that speed is reached:
KE = 1/2 mv².
This definition indicates that KE is on the rise.
Potential energy is the energy stored in a body due to its position in a gravitational field:
PE = mgh,
which increases as the object is elevated against gravitational pull.
Since both kinetic and potential energies are increasing, it follows that the total mechanical energy (ME) is also rising:
ME = PE + KE.
Answer:
17.35 × 10^(-6) m
Explanation:
Mass; m = 50 kg
Weight; W = 554 N
From the formula:
W = mg
This simplifies to; 554 = 50g
g = 554/50
g = 11.08 m/s²
Also, using the formula;
mg = GMm/r²
hence; g = GM/r²
Rearranging gives;
r = √(GM/g)
With G as a known constant of 6.67 × 10^(-11) Nm²/kg²
r = √(6.67 × 10^(-11) × 50/11.08)
r = 17.35 × 10^(-6) m
Answer:
x₂=2×1
Explanation:
According to the work-energy theorem, we can assume that the gravitational potential energy at the lowest point of compression is zero since the kinetic energy change is 0;
mgx-(kx)²/2 =0 where m refers to the object's mass, g indicates the acceleration due to gravity, k denotes spring constant, and x represents the spring's compression.
mgx=(kx)²/2
x=2mg/k----------------compression when the object is at rest
However, ΔK.E =-1/2mv²⇒kx²=mv² -----------where v symbolizes the object's velocity and K.E signifies kinetic energy
Thus, if kx²=mv² then
v=x *√(k/m) ----------------where v=0
<pDoubling v results in multiplying x *√(k/m) by 2, leading to x₂ being double x₁
For motion in a circle.
Centripetal acceleration is calculated as mv²/r = mω²r
where v represents linear velocity, r equals radius which is diameter/2 equating to 1/2 or 0.5m
. Here, m is the mass of the object, which is 175g or 0.175kg.
The angular speed, ω, is derived from Angle covered / time
= 2 revolutions per 1 second
= 2 * 2π radians for each second
= 4π radians per second
Thus, Centripetal Acceleration = mω²r = 0.175*(4π)² * 0.5. Utilize a calculator
≈13.817 m/s²
. The acceleration's magnitude is approximately 13.817 m/s² and it is oriented towards the center of the circular path.
The tension in the string equates to m*a
= 0.175*13.817
= 2.418 N
