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Serhud
1 month ago
14

Daring Darless wishes to cross the Grand Canyon of the Snake River by being shot from a cannon. She wishes to be launched at 65

∘ relative to the horizontal so she can spend more time in the air waving to the crowd.
With what minimum speed must she be launched to cross the 520-m gap?
Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
ValentinkaMS [3.4K]1 month ago
3 0

Answer:

To successfully navigate the 520 m gap, she needs to be launched at a minimum speed of 57.67 m/s.

Step-by-step explanation:

Given:

The projectile's launch angle is, \theta =65°

The range covered by the projectile is, R=520 m.

Gravity's acceleration is, g=9.8\ m/s^2

To determine the minimum speed necessary for crossing the gap, we use the formula related to the range of the projectile.

The projectile's range is calculated as:

R=\frac{v_{0}^2\sin2\theta}{g}

By substituting the provided values, we can find the minimum speed, v_0.

520=\frac{v_{0}^2\sin(2(65))}{9.8}\\520\times 9.8=v_{0}^2\sin(130)\\5096=1.532v_{0}^2\\v_0^2=\frac{5096}{1.532}\\v_0^2=3326.371\\v_0=\sqrt{3326.371}=57.67\textrm{ m/s}

Thus, in order to clear the 520 m gap, she must be launched at a minimum speed of 57.67 m/s.

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If a 50.0-kg mass weighs 554 n on the planet saturn, calculate saturn’s radius
ValentinkaMS [3465]

Answer:

17.35 × 10^(-6) m

Explanation:

Mass; m = 50 kg

Weight; W = 554 N

From the formula:

W = mg

This simplifies to; 554 = 50g

g = 554/50

g = 11.08 m/s²

Also, using the formula;

mg = GMm/r²

hence; g = GM/r²

Rearranging gives;

r = √(GM/g)

With G as a known constant of 6.67 × 10^(-11) Nm²/kg²

r = √(6.67 × 10^(-11) × 50/11.08)

r = 17.35 × 10^(-6) m

8 0
1 month ago
A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90 s. You may ignore air
Sav [3153]

Answer:

Height (h) = 17 m

Velocity (v) = 18.6 m/s

Explanation: This problem can be solved using kinematic motion equations.

Given Data

Initial velocity (u) = 0

Acceleration (a) = g

Time (t) = 1.9 seconds

First, we calculate the height.

s=ut+0.5at^2\\h=ut+0.5at^2\\h=0*1.9+0.5*9.81*1.9^2\\h=17.707 m

Then, we find the final velocity

v=u+at\\v=0+9.81*1.9\\v=18.639

The acceleration graph is a linear representation described by y=9.8, as it remains constant:

The velocity graph can be represented by y=9.8x (where y signifies velocity and x indicates time):

The displacement graph can be described as y=4.9x^2 (with x as time and y as displacement):

These graphs apply exclusively from x=0 to x=1.9, so disregard other sections of the graphs.

5 0
2 months ago
A policeman in a stationary car measures the speed of approaching cars by means of an ultrasonic device that emits a sound with
Ostrovityanka [3204]

Answer:

The beats frequency measures approximately

4.4 kHz

Explanation:

The beat frequency arises from the original ultrasound frequency, f=41.2 kHz, and the frequency of the sound reflected off the car, f':

f_B = f'-f (1)

To calculate the frequency of the reflected sound, we apply the Doppler effect formula:

f'=\frac{v}{v-v_s}f

where

v = 340 m/s, the speed of sound

v_s =33.0 m/sis the velocity of the car

f=41.2 kHzis the frequency of the sound emitted

By substituting values,

f'=\frac{340 m/s}{340 m/s-33.0 m/s}(41.2 kHz)=45.6 kHz

Thus, the beat frequency (1) is

f_B = 45.6 kHz - 41.2 kHz=4.4 kHz

3 0
1 month ago
Read 2 more answers
The iron ball shown is being swung in a vertical circle at the end of a 0.7-m string. how slowly can the ball go through its top
Keith_Richards [3271]
<span>A centripetal force maintains an object's circular motion. When the ball is at the highest point, we can assume that the ball's speed v is such that the weight of the ball matches the required centripetal force to keep it moving in a circle. Hence, the string will not become slack. centripetal force = weight of the ball m v^2 / r = m g v^2 / r = g v^2 = g r v = sqrt { g r } v = sqrt { (9.80~m/s^2) (0.7 m) } v = 2.62 m/s Thus, the minimum speed for the ball at the top position is 2.62 m/s.</span>
6 0
1 month ago
An astronomer observes that the wavelength of light from a distant star is shifted toward the red part of the visible spectrum.
Yuliya22 [3333]

Answer:

The separation between Earth and the star is growing.

Explanation:

When we witness the electromagnetic radiation of an object shifting towards the blue spectrum, it indicates that the object is moving closer, which compresses the light waves and decreases the wavelength towards blue, referred to as blueshift.

Conversely, when an object retreats from us rapidly, its light waves are stretched, resulting in a longer wavelength that shifts towards the red part of the spectrum. This shift is termed redshift.

The alteration of wavelength and frequency due to relative motion (approaching or receding) is explained by the Doppler effect.

In this case, since the light we detect from the star has transitioned to the red part of the spectrum, we can infer that it is moving away from Earth, indicating that the distance between the star and Earth is increasing.

7 0
12 days ago
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