Answer:
Step-by-step explanation:
For resolution, the Euclidean division is necessary:
- The polynomial is expressed as 16-2x³-6x²+x+9=-2x³-6x²+x+9
- We will divide this by: 4+3x-2=3x+2 and analyze the remainder
A visual representation of the process is provided
- The remainder is 47/9, hence the value to subtract is 47/9
Answer:
13%
Detailed breakdown:
Information provided:
- MP = 2080
- Discount = d%
- VAT = (d-2)%
- Cost = 1997.84
Applying the discount:
- 2080 - d% = 2080*(1 - 0.01d)
Including VAT:
- 2080*(1 - 0.01d) + (d - 2)%
- 2080*(1 - 0.01d) * (1 + (d -2)/100)
- 2080*(1 - 0.01d) * (0.98 + 0.01d) = 1997.84
- (1 - 0.01d)(0.98 + 0.01d) = 1997.84/2080
- 0.98 + 0.01d - 0.0098d - 0.0001d² = 0.9605
- - 0.0001d² + 0.0002d + 0.98- 0.9605 = 0
- 0.0001d²- 0.0002d - 0.0195 = 0
- d² - 2d + 195 = 0
Solving this quadratic equation yields:
Therefore
Answer: The most significant angle created during his journey appears at the mall, between his house and the library.
Step-by-step explanation:
Hi, since this scenario forms a right triangle (refer to the attached image), the angle between his house and the library measures 90°.
For a right triangle, the total of its internal angles equals 180°, making the right angle (90°) the largest among them.
Thus, the angle at the mall, between his house and the library, is indeed the largest angle formed during his trip.
If you need further clarification or have questions, feel free to ask!
To tackle this sinusoidal question, we begin with the following: Using the formula; g(t)=offset+A*sin[(2πt)/T+Delay] According to sinusoidal theory, the duration from trough to crest is typically half of the wave's period. Here, T=2.5 The peak magnitude is calculated as: Trough-Crest=2.1-1.5=0.6 m amplitude=1/2(Trough-Crest)=1/2*0.6=0.3 The offset from the center of the circle becomes 0.3+1.5=1.8 As the delay is at -π/2, the wave will commence at the trough at [time,t=0]. Plugging these values into the formula gives: g(t)=1.8+(0.3)sin[(2*π*t)/2.5]-π/2] g(t)=1.8+0.3sin[(0.8πt)/T-π/2]
