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snow_tiger
7 days ago
13

Mr. Dennis travels 27.2 miles to work each day.

Mathematics
You might be interested in
for the level 3 course, examination hours cost twice as much as workshop hours and workshop hours cost twice as much as lecture
Leona [12618]

Answer:

The hourly rate for lectures is $7.33

Step-by-step explanation:

* Let's break down how to tackle the problem.

- For the level 3 course, examination hours are priced at double that of workshop hours.

- Workshop hours cost twice the rate of lecture hours.

- The total includes examination, workshop, and lecture hours.

- Examination lasts 3 hours, workshops 24 hours, and lectures 12 hours.

* Let’s denote the cost of lecture hours as $x per hour.

∴ The lectures cost $x per hour.

∵ Workshop charge is twice that of lectures

∴ Workshop hours cost 2(x) = 2x per hour.

∵ Examination fees are double that of workshop hours

∵ The workshop cost is 2x

∴ Examination fees are 2(2x) = 4x per hour.

- Combining costs for level 3 gives us the total of lecture, workshop, and examination hours.

∵ 12 hours for lectures

∵ 24 hours for workshops

∵ 3 hours for examinations

∵ Thus the total cost for level 3 = 12(x) + 24(2x) + 3(4x).

∴ Total cost for level 3 = 12x + 48x + 12x.

∵ Therefore, total cost = $528.

∴ 12x + 48x + 12x = 528.

∴ 72x = 528; hence we divide both sides by 72.

∴ x = 7.33.

∵ x represents the cost of lecture hours per hour.

∴ Therefore, the hourly price for lectures is $7.33.

6 0
3 months ago
A battery with 20% percent of its full capacity is connected to a charger. Every minute that passes, an additional 5% percent of
Inessa [12570]

Response:

The connection between battery capacity and time is:

Y=0.05t+0.2

The associated graph is provided.

Step-by-step explanation:

We will plot the battery's charged capacity against time.

The charging rate remains steady; hence, the relationship is linear.

Initially, at time t=0, the battery's capacity measures 0.2 (or 20%).

With each passing minute, an additional 5% of its capacity is accumulated. Thus, at t=1, the capacity becomes 0.2 + 0.05 = 0.25 (or 25%).

We can derive the slope for the linear function as:

m=\dfrac{\Delta Y}{\Delta t}=\dfrac{0.05}{1}=0.05

Consequently, the correlation between battery capacity and time is:

Y=0.05t+0.2

3 0
2 months ago
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