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rusak2
5 days ago
9

A woman deposits 100 EUR in her daughter's bank account on her first birthday. On every subsequent birthday, she deposits 10 EUR

more than she deposited the previous year, so on her second birthday, she deposits 110 EUR, and on her third birthday she deposits 120 EUR.
By the time her daughter is 21 years old, how much money has been deposited in her account?
Mathematics
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Two birds sit at the top of two different trees. The distance between the first bird and a birdwatcher on the ground is 32 feet.
Svet_ta [12734]

Response:

Step-by-step breakdown:

When you sketch that diagram (great description, by the way!), what you essentially have is a right triangle with a base of 32 and a hypotenuse of 45. The right angle resides at one of the base's ends, and x represents the vertex angle. We must find this vertex angle first to determine the angle of depression from the second bird to the watcher. The side measuring 32 is opposite to angle x, with 45 being the hypotenuse; hence, the trigonometric relation we need is sine:

sin(x)=\frac{32}{45} and

sin(x) =.711111111

Go to your calculator, press the 2nd key followed by the sin key, and your display will show:

sin^{-1}(

then, enter in your decimal.711111111 and hit equals. You should arrive at an angle of 45.325. That angle is x. However, that's not the angle of depression. The angle of depression is the complementary angle to x.

Angle of depression = 90 - angle x and

Angle of depression = 90 - 45.325, resulting in

Angle of depression = 44.67 or 44.7 degrees.

8 0
1 month ago
A school fundraiser sells 1,200 raffle tickets. Each ticket costs $2. There is one grand prize worth $100 and 5 smaller prizes w
Svet_ta [12734]
The expected loss is $1.83. Step-by-step explanation: The average value for each ticket is calculated as... ($100 + 5($20)) / 1200 = $200 / 1200 ≈ $0.1667 ≈ $0.17. Since purchasing a ticket costs $2.00, your anticipated value becomes... -$2.00 + 0.17 = -$1.83, leading to a loss of $1.83.
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Suppose we are given 4 sets A, B, C, D such that A ⊆ B and C ⊆ D such that A and C have no elements in common. Prove or give a c
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Here’s a counterexample: consider

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It's accurate that A\subseteq B and C\subseteq D and that A\cap C=\emptyset, but A\cap D = \{5\}

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