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AURORKA
2 months ago
6

Choose a plant or animal that you think is interesting. describe some of the threats or challenges

Biology
1 answer:
garik1379 [2K]2 months ago
8 0

Kung bibigyan ako ng pagkakataon na pumili ng kakaibang halaman o hayop, ang pipiliin ko ay ang "cactus."

Paliwanag:

Napakaganda ng "cactus" dahil sa kanyang kakayahang mabuhay sa disyerto o sa mga panahong tagtuyot. Hindi rin mahirap alagaan ang mga ito. Subalit, ang plantitong ito ay biktima ng ilang mga banta na pwedeng magdulot ng panganib sa kanyang uri.

  • Isa sa mga banta ay ang "sobra-sobrang pagkuha ng cacti." Madalas na ito ay ibinebenta bilang pandekorasyon na halaman dahil sa maraming gamit nito.
  • May mga peste tulad ng snails at slugs na umaatake rito taun-taon. Isa itong paboritong kainin ng mealy bugs, red spider mites, gnats, flies, atbp.
  • Maraming tao ang mali ang pagkaintindi sa pangangailangan ng cactus sa tubig. Madalas nilang sobrang diligan ang halaman na nagiging sanhi upang mahawahan ito ng mga bakterya, virus at fungi.
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Imagine that two unlinked autosomal genes with simple dominance code in goats for size, where T is tall and t is short, and for
enyata [2506]

Answer:

(A) 0.0625

(B) 25%

Explanation:

A

With the following:

T indicates tall

t indicates short

R indicates red

r indicates tan.

When a short tan male goat mates with a tall red female goat of an unknown genotype;

Let's analyze separately;

A short tan male goat = ttrr

The female goat’s genotype is not specified but it is known to be tall and red

∴ We determine that she must be T_ R_;

the potential genotype probability of the female for each allele could be:

- T

T

or Tt- RR

or R

r

Nonetheless, from earlier discussion;

the chance that the female is Tt = \frac{1}{2}

the probability of the female being Rr = \frac{1}{2}

the probability of passing on the recessive allele 't' to offspring = \frac{1}{2}

the probability of passing on the recessive allele 'r' to offspring = \frac{1}{2}

∴ the likelihood that the pairing would yield short, tan offspring (ttrr) stands at;

= (\frac{1}{2})^{4}

= (\frac{1}{16})

= 0.0625

(B)

In pea plants, one is homozygous recessive for both traits, leading to the cross of Yy Rr × yy rr. Determine the green and round offspring percentage.

For Color, let:

Y = Yellow

y = Green

For shape, let;

R = Round

r = wrinkled

If a cross occurs between Yy Rr × yy rr. (yellow round and green wrinkled)

the ratio of green and round offspring will be;

If Yy Rr self-crosses; various traits (YR, Yr, yR, yr)

yy rr will produce (yr, yr)

                   YR                    Yr                    yR                    yr

yr                 YyRr                 Yyrr                 yyRr                 Yyrr

yr                 YyRr                 Yyrr                 yyRr                 Yyrr

                   Yellow              Yellow            Green              Green

                   Round               Wrinkled        Round              Wrinkled

                   Thus, the percentage of green and round offspring based on the above is:

=

%

\frac{2}{8}*100%=

%

\frac{1}{4}*100=

25%

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