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4 days ago

A group of students must conduct an experiment to determine how the location of an applied force on a classroom door affects the

rotational motion of the door. The rotational inertia of the door about its hinges is known. The initial angular velocity of the door is zero. Which of the following lists what measuring devices the students need and the measurements they should take to collect the necessary data to test the relationship between a torque exerted on the door and the change in angular velocity of that object about the hinges of the door? Justify your selection.
a. A protractor to measure the angular displacement of the door and a meterstick to measure the radial distance from the door's hinges to the location where the force is applied.
b. A stopwatch to measure the time interval during which the force is applied and a meterstick to measure the radial distance from the door's hinges to the location where the force is applied
c. A force probe to measure the applied force on the door, and a stopwatch to measure the time interval during which the force is applied, and a meterstick to measure the radial distance from the door's hinges to the location where the force is applied.
d. A stopwatch to measure the time interval during which the force is applied, a force probe to measure the applied force on the door, a protractor to measure the angular displacement of the door, and a meterstick to measure the radial distance from the door's hinges to the location where the force is applied.

Physics

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Two trains are headed towards each other on the same track unbeknownst to the engineers. One departs San Francisco. Its average

ValentinkaMS [3465]

Answer:

7.166 hours = 430 minutes.

Explanation:

As both trains are approaching each other on the same track, their relative speed is the sum of their individual speeds. Hence, the time until they intersect (and inevitably collide) is determined by how long it takes for speeds of 65 mph and 55 mph to cover the total distance of 860 miles. One train will cover part of the distance, while the other will cover the remainder. To calculate the required time, we can apply the formula:

1 hour ---> 120 miles

X ----> 860 miles; hence X = (860 miles * 1 hour)/120 miles = 43/6 hours = 7.16666 hours. To convert this into minutes, recall that 1 hour equals 60 minutes; therefore, 43/6 hours * 60 minutes/hour = 430 minutes.

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3 months ago

The height of a typical playground slide is about 6 ft and it rises at an angle of 30 ∘ above the horizontal.

Maru [3345]

Answer:

The coefficient of kinetic friction is found to be 0.432.

Explanation:

Comprehensive steps and derivations with necessary substitutions are detailed in the attached document.

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3 months ago

A supersonic nozzle is also a convergent–divergent duct, which is fed by a large reservoir at the inlet to the nozzle. In the re

Softa [3030]

Answer:

155.38424 K

2.2721 kg/m³

Explanation:

$P_1$ = Reservoir pressure = 10 atm

$T_1$ = Reservoir temperature = 300 K

$P_2$ = Exit pressure = 1 atm

$T_2$ = Exit temperature

$R_s$ = Specific gas constant = 287 J/kgK

$\gamma$ = Specific heat ratio = 1.4 for air

Assuming isentropic flow

$\frac{T_2}{T_1}=\frac{P_2}{P_1}^{\frac{\gamma-1}{\gamma}}\\\Rightarrow T_2=T_1\times \frac{P_2}{P_1}^{\frac{\gamma-1}{\gamma}}\\\Rightarrow T_2=00\times \left(\frac{1}{10}\right)^{\frac{1.4-1}{1.4}}\\\Rightarrow T_2=155.38424\ K$

Flow temperature at exit is 155.38424 K

Density at exit can be derived using the ideal gas equation

$\rho_2=\frac{P_2}{R_sT_2}\\\Rightarrow \rho=\frac{1\times 101325}{287\times 155.38424}\\\Rightarrow \rho=2.2721\ kg/m^3$

Flow density at exit measures 2.2721 kg/m³

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3 months ago

A small block of mass 200 g starts at rest at A, slides to B where its speed is vB=8.0m/s,vB=8.0m/s, then slides along the horiz

serg [3582]

Answer

Data provided:

mass of the block = 200 g = 0.2 Kg

Velocity at A = 0 m/s

Velocity at B = 8 m/s

distance of slide = 10 m

height of the block = 4 m

calculation for the block's potential energy

P = m g h

P = 0.2 x 9.8 x 4

P = 7.84 J

kinetic energy calculated as

$KE = \dfrac{1}{2}mv^2$

$KE = \dfrac{1}{2}\times 0.2 \times 7.84^2$

$KE =6.14 J$

Work done = P - KE

work = 7.84 - 6.14

work = 1.7 J

b) using the formula v² = u² + 2 a s

0 = 8² - 2 x a x 10

a = 3.2 m/s²

ma - μ mg = 0

$\mu = \dfrac{a}{g}$

$\mu = \dfrac{3.2}{9.8}$

$\mu = 0.327$

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3 months ago

The mass of a particular eagle is twice that of a hunted pigeon. Suppose the pigeon is flying north at ????????,2=17.9vi,2=17.9

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The speed is V=27.24 m/s. We need to utilize the linear momentum conservation principle: The eagle's speed can be defined via two components: Since speed is a scalar quantity.

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2 months ago