Answer:
a
The value at a point inside is Zero
b
The electric field is 
Explanation:
We know from the problem that
The charge magnitude is 
The radius of the spherical ball is 
According to Gauss’s law, the enclosed charge within a conductor is zero which indicates that the electric field within the spherical ball is zero
On the outside, the electric field around the spherical ball is mathematically expressed as
Here a denotes a point outside the spherical ball with its value of 
and k represents Coulomb's constant, valued at
=> 
=>
Response:
0.60 m/s
Details:
The average speed between times t = a and t = b can be expressed as:
v_avg = (x(b) − x(a)) / (b − a)
Given the function x(t) = 0.36t² − 1.20t, and considering the interval from 1.0 to 4.0:
v_avg = (x(4.0) − x(1.0)) / (4.0 − 1.0)
v_avg = [(0.36(4.0)² − 1.20(4.0)) − (0.36(1.0)² − 1.20(1.0))] / 3.0
v_avg = [(5.76 − 4.8) − (0.36 − 1.20)] / 3.0
v_avg = [0.96 − (-0.84)] / 3.0
v_avg = 0.60
The average speed calculated is 0.60 m/s.
Fire extinguishers are commonly colored red, which aligns with the red of fire trucks and the general association of red with emergencies. Although there is no official standard, altering the colors could lead to confusion, potentially endangering lives. Therefore, it seems that red will likely remain the color of fire extinguishers for the foreseeable future.
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The required lift force is approximately 866.92 N. To determine this, we first establish the shark's mass at 92 kg and its density at 1040 kg/m³. The volume of the shark is calculated by dividing mass by density, yielding 0.08846 m³. The buoyant force acting on the shark is then determined by multiplying the volume by the density of water and gravity, resulting in a lift force of 866.92 N.
The result is -15.625 m/s².
Acceleration signifies the alteration of velocity over a specified duration. It can be calculated with this formula:
Where:
vf = final velocity
vi = initial velocity
t = time
Let’s examine the information provided in your query:
Initially, the vehicle was traveling at 25 m/s before coming to a halt. Thus, it was in motion and subsequently ceased moving, indicating that the final velocity is 0 m/s.
However, we notice that the problem does not provide a time value. We need to determine the time taken from when it was in motion to when it reached the traffic light located 20 m away.
The time can be calculated using the kinematics equation:
We derive the equation by substituting the known values first.
The duration from when it was in motion until it stopped is 1.6s. Now we can utilize this in our acceleration calculation.
It is important to note that the acceleration is negative, indicating the vehicle slowed down.
