After two bites, the weight of the hamburger is recorded at 160g.
Each bite removes 20% of the burger's total weight, so to uncover the weight prior to the bites, we calculate it based on the percentage that remains.
The initial weight stands at 160g. Given that 20% of the weight was lost during a bite, we should divide this weight by the remaining percentage after the bite:

After a bite, 80% of the burger is what remains. Convert this percentage into a decimal by dividing it by 100:

Now, let's divide the original weight by this figure:

Before the second bite, the weight of the hamburger was 200g.
The same method will apply for the first bite. Initially, it weighed 200g, with 80% still intact after the initial bite. Since 80% converts to 0.8 in decimal form, divide 200 by 0.8:

Thus, the original weight of the hamburger prior to any bites was
250 grams.
Respuesta:
1/16 2/16 3/16 4/16 5/16 6/16 7/16 8/16 9/16 10/16 11/16 12/16
Explicación paso a paso:
Para identificar las brocas existen dos aspectos a considerar:
1.- Las fracciones que comparten el mismo denominador aumentan en orden ascendente a medida que los numeradores incrementan, lo que significa que entre
9/16 3/16 7/16 5/16 11/16 el orden sería (de menor a mayor)
3/16 5/16 7/16 9/16 11/16
2.- Fracciones con diferentes denominadores pueden convertirse a un denominador común /16 multiplicando la fracción, por ejemplo
1/4 = 1*4/4*4 = 4/16
Aplicando este método, todas las fracciones se transforman al formato mencionado previamente y se organizan
1/4 = 4/16
3/8 = 6/16
1/2 = 8/16
5/8 = 10/16
1/8 = 2/16
Por lo tanto, hay diez brocas, comenzando con 1/16 hasta la número 12 que es 12/16
Finalmente, el orden sería:
1/16 2/16 3/16 4/16 5/16 6/16 7/16 8/16 9/16 10/16 11/16 12/16
Answer:
mCEA = 90ᴼ, as CEA forms a right angle, and by definition, right angles measure 90ᴼ.
The angle CEF is classified as a straight angle as it combines two right angles (CEA and AEF), equating to 180ᴼ altogether. Straight lines are defined to measure 180ᴼ.
AEF is determined to be a right angle as CEA is already a right angle, and since CEF is a straight line, AEF must also be a right angle.
The estimated probability that the code consists solely of odd digits is 0.02381.