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Sloan
2 months ago
12

Six random samples were taken each year for three years. The table shows the inferred population for each type of fish for each

year.
A 4-column table with 3 rows. Column 1 is labeled Year with entries 1, 2, 3. Column 2 is labeled Population Trout with entries 77, 83, 92. Column 3 is labeled Population Catfish with entries 57, 76, 80. Column 4 is labeled Population Bass with entries 58, 40, 31.

Which conclusion is supported by the data from the multiple-year samples? Check all that apply.
The number of bass increased over time.
The number of bass decreased over time.
The number of catfish increased over time.
The number of catfish remained the same.
The fish population decreased over time.
Mathematics
2 answers:
tester [12.3K]2 months ago
8 0

The findings are:

  • Bass numbers have declined over time
  • Catfish numbers have grown over time.

Step-by-step explanation:

By organizing the data in a table format, one can visualize patterns and draw conclusions

Year        Trout     Catfish    Bass    Total

1                  77         57          58        192

2                  83        76          40        199

3                   92        80         31         203

The table indicates;

  • Over time, the bass population has decreased.
  • There has been an increase in the number of catfish over time
  • The Trout population has risen over time
  • Overall fish population has increased over the years

Learn More

Reading tables:

Keywords: random,samples,years,table,fish,years

babunello [11.8K]2 months ago
8 0

Answer:

the correct choice is B

Step-by-step explanation:

no

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In a GP if T3 = 18 and T6 = 486 Find:- T10
lawyer [12517]

Answer:

The 10th term in the geometric progression is 29.

Step-by-step explanation:

Given: In a geometric series, [T3 = 18] and [T6 = 486].

To find: The term [T10]?

Solution:

A geometric sequence takes the form [a, ar, ar^2,...]

Where, a represents the first term, and r denotes the common ratio.

The nth term is expressed as [Tn = a * r^(n-1)]

From the information provided: [T3 = a * r^2 = 18]

And [T6 = a * r^5 = 486]

By dividing the second equation by the first:

[(a * r^5) / (a * r^2)] = 486 / 18

[r^3 = 27]

Taking the cube root provides: r = 3.

Inserting r into one of the equations allows us to solve for a.

Substituting r gives: [T3 = a * r^2 = 18]

Thus, the first term is a = 2, and the common ratio is r = 3.

The 10th term in the geometric progression is computed as:

[T10 = a * r^(10-1)]

[Thus, T10 = 29.]

8 0
2 months ago
Read 2 more answers
Thursday is ladies night at the slurp and burp bar and grill. all adult beverages are $ 1.25 for women and $ 2.50 for men. a tot
babunello [11817]
The ratio of women to men is 34 to 382. To find the total sales, we compute 382 multiplied by 2.50, resulting in $955. For women, the calculation is 34 multiplied by 1.25, which equals $42.50. Therefore, summing these amounts gives us $955 + $42.50 = $997.50.
7 0
1 month ago
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The Sears Tower, at 1,451 feet, is one of the tallest structures in the United States. A penny is thrown from the top of the tow
Leona [12618]

Answer:

The formula representing the penny's height as a function of time is:

h(t)=1451-16t^2

After 7 seconds, the height of the penny will reach 667 feet.

Step-by-step explanation:

The penny experiences free fall.

With an initial velocity of zero and an initial height of h(0)=1,451.

Gravity acts as the acceleration, measured as g=32 ft/s^2.

The model can be initiated by analyzing speed:

dv/dt=-g\\\\v(t)=v_0-gt=-gt

Then, the height is expressed as:

dh/dt=v(t)=-gt\\\\h(t)=h_0-\dfrac{gt^2}{2}=1451-\dfrac{32}{2}t^2\\\\\\h(t)=1451-16t^2

The height of the penny at approximately 7 seconds can be calculated as:

h(7)=1451-16(7^2)=1451-16*49=1451-784=667

After 7 seconds, the penny will stand at a height of 667 feet.

6 0
3 months ago
If you ask three strangers about their birthdays, what is the probability:
Inessa [12570]
Part A:

The probability that all three strangers have their birthdays on a Wednesday is calculated as

\left( \frac{1}{7} \right)^3= \bold{\frac{1}{343}}



Part B:

The probability that the birthdays of the three individuals fall on distinct days throughout the week is calculated as

\left( \frac{1}{7} \right)\left( \frac{1}{6} \right)\left( \frac{1}{5} \right)= \bold{\frac{1}{210}}



Part C:

The probability that none of the three have their birthdays on a Saturday is determined by

\left( \frac{6}{7} \right)^3= \bold{\frac{216}{343}}
8 0
1 month ago
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