Two competing gyms each offer childcare while parents work out. Gym A charges $9.00 per hour of childcare. Gym B charges $0.75 p

A is confirmed as correct since -13 falls within the domain of g(x), and 20 is included in its range. For g(x), the inequality holds: -20 < -13 < 5 and -5 < 20 < 45. B is incorrect since the number 4 exists within the domain of g(x), but -11 is not within its range, represented by -20 < 4 < 5 and -11 < -5. C is likewise incorrect, as it is stated that g(0) equals -2. D is also false since 7 does not belong to the domain of g(x).

8x²-8x+2-5+x reduces to 8x² - 7x - 3
Therefore, we find g = 7 and h = 3

Answer:

B

Step-by-step explanation:

Answer:

a) 2.60x10^-7

b) 5.31x10^-5

c) 2.19x10^-3

Step-by-step explanation:

X=the number of hits

Probability can be determined by taking the number of successful outcomes and dividing it by the total number of possible outcomes.

Now

a) P(X=6)=P({1, 1, 1, 1, 1, 1})=6/40*5/39*4/38*3/37*2/36*1/35=2.60x10^-7

b) P(X=5)=P({0, 1, 1, 1, 1, 1})+P({1, 0, 1, 1, 1, 1})+...+P({1, 1, 1, 1, 1, 0}), and each scenario carries the same probability

P(X=5)=6P({1, 1, 1, 1, 1, 0})=6*(6/40*5/39*4/38*3/37*2/36*34/35)=5.31x10^-5

c) P(X=4)=P({0, 0, 1, 1, 1, 1})+...+P({1, 1, 1, 1, 0, 0}), where each case has an identical probability.

If you're referring to the number of outfit combinations John can create, he has 12 sock pairs he can wear with any of his 3 shoe pairs, 5 pant options, and 5 shirts. In total, there are 12 ways to choose socks, 3 for shoes, 5 for pants, and another 5 for shirts, leading to 12 * 3 * 5 * 5 = 900 combinations.