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forsale
13 hours ago
15

A square weightless frame ABCD with the side a is rotating around the side AB with the constant angular velocity ω1. A uniform d

isk of radius R and mass m is rotating around the frame’s diagonal AC with the constant angular velocity ω2. The center of the disk coincides with the center of the frame. Assuming ω1 = ω2 = ω find
a. The kinetic energy of the system.
b. The magnitude of the torque that needs to be applied to the axis AB to keep it (the axis AB) still.

Physics
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A beaker of negligible heat capacity contains 456 g of ice at -25.0°C. A lab technician begins to supply heat to the container a
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The response is 176 minutes. The translation of 456 g equals 0.456 kg. The specific heat of ice is 2093 J kg⁻¹, used to calculate heat required for a 25-degree rise, determined by mass multiplied by specific heat and temperature increase. The necessary calculations yield a total heat load of 176164 J. Finally, by dividing heat required by heat supply rate, we ascertain that it will take approximately 176.16 minutes.
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2 months ago
A boy on a bicycle approaches a brick wall as he sounds his horn at a frequency 400 hz. the sound he hears reflected back from t
Softa [3030]
The question pertains to the change in frequency of a wave noted by an observer moving in relation to the source, indicating that the concept to invoke is "Doppler's effect."

The standard formula for the Doppler effect is:
f = (\frac{g + v_{r}}{g + v_{s}})f_{o} -- (A)

Note that we don’t need to be concerned with the signs here, as all entities are moving toward each other. If something was moving away, a negative sign would apply, but that is not relevant to this scenario.

Where,
g = Speed of sound = 340m/s.
v_{r} = Velocity of the observer relative to the medium =?.
v_{s} = Velocity of the source in relation to the medium = 0 m/s.
f_{o} =  Frequency emitted from the source = 400 Hz.
f = Frequency recognized by the observer = 408 Hz.

Substituting the given values into equation (A) will yield:

408 = ( \frac{340 + v_{r}}{340 + 0})*400

\frac{408}{400} = \frac{340 + v_{r}}{340}

Solving the above will result in,
v_{r} = 6.8 m/s

The correct result = 6.8m/s



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0.00066518 Nm
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