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Stolb23
1 month ago
15

A wire has an electric field of 6.2 V/m and carries a current density of 2.4 x 108 A/m2. What is its resistivity

Physics
1 answer:
Softa [3K]1 month ago
5 0

Response:

The resistivity can be expressed as \rho = 2.5 *10^{-8} \ \Omega \cdot m

Clarification:

According to the information provided,

    The value of the electric field measures  E = 6.2 V/m

     The density of current is given as  J = 2.4 *10^{8} \ A/m^2

Typically, resistivity is represented in mathematical terms as

         \rho = \frac{E}{J}

by inserting values

        \rho = \frac{6.2}{2.4 *10^{8}}

        \rho = 2.5 *10^{-8} \ \Omega \cdot m

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